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Arithmetic : Level 1 Test -5
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Question 1 |
Anu is a working partner and Bimla is a sleeping partner in a business. Anu puts in Rs. 5000 and Bimla puts in Rs. 6000. Anu receives 12.5% of the profit for managing the business and the rest is divided in proportion to their capital. What does each get out of a profit of Rs. 880?
Rs. 400 and Rs. 480 | |
Rs. 460 and Rs. 420 | |
Rs. 450 and Rs. 430 | |
Rs. 470 and Rs. 410 |
Question 1 Explanation:
12.5% of profit = (12.5/100) x 880 = Rs. 110
Remaining Rs. 770 is divided in the ratio = 5000 : 6000 = 5 : 6
Profit of Anu = 5/11 x 770 + 110 = Rs. 460
Profit of Bimla = 6/11 x 770 = Rs. 420
Remaining Rs. 770 is divided in the ratio = 5000 : 6000 = 5 : 6
Profit of Anu = 5/11 x 770 + 110 = Rs. 460
Profit of Bimla = 6/11 x 770 = Rs. 420
Question 2 |
X contributes Rs. 1500 and Y Rs. 900 in a business. X is a sleeping partner and Y gets 10% of the profit for management and the rest of the profit is divided in the proportion of their capital. If the profit is ~ 800, what is the share of Y?
Rs. 375 | |
Rs.360 | |
Rs. 350 | |
Rs. 450 |
Question 2 Explanation:
10% of profit = 10/100 x 800 = Rs. 80
Remaining Rs. 720 is divided in the ratio = 1500 : 900 = 5: 3
Share of Y = 3/8 x 720 + 80 = Rs. 350
Hence option c
Remaining Rs. 720 is divided in the ratio = 1500 : 900 = 5: 3
Share of Y = 3/8 x 720 + 80 = Rs. 350
Hence option c
Question 3 |
X and Y are partners in a business. X contributed 1/3 of the capital for 9 months and Y received 2/5 of the profits. For how long was Y's money used in the business?
4 months | |
3 months | |
2 months | |
5 months |
Question 3 Explanation:
Ratio of capital= 1/3 : 2/3 = 1 : 2
Ratio of profit 3/5 : 2/5 = 3: 2
Let Y's money was used for n months.
Therefore (1 x 9) : (2 x n) = 3: 2
n =3 months
Ratio of profit 3/5 : 2/5 = 3: 2
Let Y's money was used for n months.
Therefore (1 x 9) : (2 x n) = 3: 2
n =3 months
Question 4 |
Three numbers A, B and C are in the ratio of 12: 15 : 25. If sum of these numbers is 312, ratio between the difference of B and A and the difference of C and B is
3 : 7 | |
10 : 3 | |
3 : 10 | |
5 : 1 |
Question 4 Explanation:
Let three numbers A, B and C are 12s, 15s and 25s respectively.
12s + 15s + 25s = 312
s=312/52 =6
Therefore required ratio
(15 x 6 – 12 x 6) /(25 x 6 – 15 x 6)
= (3 x 6) /10 x 6 = 3/10
Hence the ratio will be 3 : 10
s=312/52 =6
Therefore required ratio
(15 x 6 – 12 x 6) /(25 x 6 – 15 x 6)
= (3 x 6) /10 x 6 = 3/10
Hence the ratio will be 3 : 10
Question 5 |
A car takes 15 min less to cover 75 km if it increases its speed by 10 km/h from its usual speed. How much time would it take to cover 300 km if the car travels at its usual speed?
5 h | |
51/2h | |
6 h | |
61/2 h |
Question 5 Explanation:
Let the usual speed of the car = s km/h
Since the car takes 15 min less to cover 75 km,
therefore equating the time taken in the two cases,
we get the following equation:
75/s = [75/(s+10)] + 15/60
Calculating for s, we get
s = 50 km/h
Therefore, the required time will be = 300/50 = 6 h
Since the car takes 15 min less to cover 75 km,
therefore equating the time taken in the two cases,
we get the following equation:
75/s = [75/(s+10)] + 15/60
Calculating for s, we get
s = 50 km/h
Therefore, the required time will be = 300/50 = 6 h
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