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Arithmetic: Percentage Test -4
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Question 1 |
Atish saves 20% of his salary. His salary has increased by 20% and his expenditure has increased by 30%. What is the percentage change in his savings?
20% fall | |
4% fall | |
20% rise | |
4% rise |
Question 1 Explanation:
Let A be the income.
Expenditure = 0.8 A
Savings = 0.2 A => 20%
New income = 1.2 A (since 20% rise)
New expenditure = (0.8 A) X 1.3 (Since 30% rise) = 1.04A
So, new savings = 1.2A – 1.04A = 0.16A => 16%
% decrease = (20-16)/20 X 100 = 20%.
Expenditure = 0.8 A
Savings = 0.2 A => 20%
New income = 1.2 A (since 20% rise)
New expenditure = (0.8 A) X 1.3 (Since 30% rise) = 1.04A
So, new savings = 1.2A – 1.04A = 0.16A => 16%
% decrease = (20-16)/20 X 100 = 20%.
Question 2 |
The price of mangoes has increased by 25%. By what percent the consumption needs to be reduced so that the expense on mangoes remains the same?
25% | |
33.33% | |
20% | |
None |
Question 2 Explanation:
We solve this question using the principle of constancy.
Let original price = P
Increased Price- 1.25P
Original Consumption= C
Increased Consumption= I
It is given that expense is the same, that is:
1.25 x I = P x C
I=0.8 C
% decrease = {(1-0.8)/1} X 100 = 20%
Let original price = P
Increased Price- 1.25P
Original Consumption= C
Increased Consumption= I
It is given that expense is the same, that is:
1.25 x I = P x C
I=0.8 C
% decrease = {(1-0.8)/1} X 100 = 20%
Question 3 |
The side of a square is increased by 20%. The percentage change in its area is ___
20% | |
44% | |
36% | |
400% |
Question 3 Explanation:
Area of a square: side x side
% change in area = 1.2 X 1.2 (since area = side X side) = 1.44
= 44%.
% change in area = 1.2 X 1.2 (since area = side X side) = 1.44
= 44%.
Question 4 |
If the length of a rectangle is increased by 33.33%, by what percentage should the breadth be reduced to make the area same?
20% | |
33.33% | |
25% | |
None |
Question 4 Explanation:
Area of original rectangle: L X B
Area of new rectangle: 1.33L x b
Since the areas are the same:
1.33 L x b = L x B
b = ¾ B
Decrease in breadth: 25%
Area of new rectangle: 1.33L x b
Since the areas are the same:
1.33 L x b = L x B
b = ¾ B
Decrease in breadth: 25%
Question 5 |
10. In the 2013 Lok Sabha Election, two candidates, X and Y, contested from Delhi. A secured 64% of the votes and won 84000 votes. Find the total number of votes if 20% of votes polled were invalid.
300000 | |
375000 | |
350000 | |
400000 |
Question 5 Explanation:
X got 64% of the Valid Votes, V
Y got 36% of the Valid Votes, V
Difference: 28% of V = 84000
Therefore, V = 300000
Only 80% of the total votes are valid.
Therefore total votes = 300000 * (100/80) = 375000
Y got 36% of the Valid Votes, V
Difference: 28% of V = 84000
Therefore, V = 300000
Only 80% of the total votes are valid.
Therefore total votes = 300000 * (100/80) = 375000
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