- This is an assessment test.
- To draw maximum benefit, study the concepts for the topic concerned.
- Kindly take the tests in this series with a pre-defined schedule.

## Arithmetic: Percentage Test -8

Please wait while the activity loads.

If this activity does not load, try refreshing your browser. Also, this page requires javascript. Please visit using a browser with javascript enabled.

If this activity does not load, try refreshing your browser. Also, this page requires javascript. Please visit using a browser with javascript enabled.

Congratulations - you have completed

*Arithmetic: Percentage Test -8*.You scored %%SCORE%% out of %%TOTAL%%.You correct answer percentage: %%PERCENTAGE%% .Your performance has been rated as %%RATING%% Your answers are highlighted below.

Question 1 |

Mr. X spends 20%of his monthly income on household expenditure. Out of the remaining 25%he spends on children's education,15%on transport, 15% on medicine and 10%on entertainment. He is left with Rs. 9,800after incurring all these expenditures. What is his monthly income?

Rs. 35,000 | |

Rs. 28,000 | |

Rs. 65,333 | |

Rs. 48,400 |

Question 1 Explanation:

Let Mr X’s salary be Rs p

His household expenditure=0.2p

Salary left after household expenditure=0.8p

Spending on childrens education=0.25×0.8p=0.2p

Spending on transport=.15×0.8p=0.12p

Spending on medicine=.15×0.8p=0.12p

Spending on entertainment=0.10×0.8p=0.08p

Mr X s total expenditure=0.2p+0.2p+0.12p+0.12p+0.08p=0.72p

So 0.28p=9800

p=35,000

His household expenditure=0.2p

Salary left after household expenditure=0.8p

Spending on childrens education=0.25×0.8p=0.2p

Spending on transport=.15×0.8p=0.12p

Spending on medicine=.15×0.8p=0.12p

Spending on entertainment=0.10×0.8p=0.08p

Mr X s total expenditure=0.2p+0.2p+0.12p+0.12p+0.08p=0.72p

So 0.28p=9800

p=35,000

Question 2 |

Arnan's expense is 30% more than Vimal's expense and Vimal's expense is 10% less than Raman’s expense. If the Sum of their expenses, is Rs.6447, then what would be the Aman's expense?

Rs. 2,200 | |

Rs. 2,457 | |

Rs. 1.890 | |

Rs. 2,100 |

Question 2 Explanation:

Let Raman's expense be p

Expense of Vimals=0.9p

Expense of Arnans=1.3×0.9p=1.17p

So 3.07p=6447

p=2100

Arnan's expense =1.17×2100=2457

Expense of Vimals=0.9p

Expense of Arnans=1.3×0.9p=1.17p

So 3.07p=6447

p=2100

Arnan's expense =1.17×2100=2457

Question 3 |

In a school there are 2000 students out of whom 36 per cent are girls. Each boy's monthly fee is Rs 480 and each girl's monthly fee is 25 per cent less than a boy. What is the total of the monthly fees of girls and boys together?

Rs 8,73,400 | |

Rs 8,67,300 | |

Rs 8,76,300 | |

Rs 8,73,600 |

Question 3 Explanation:

Girls fees=0.75×480=360

Number of girls=36/100×2000=720

Number Of boys=64/100×2000=1280

Total monthly fees=360×720+480×1280=873600

Number of girls=36/100×2000=720

Number Of boys=64/100×2000=1280

Total monthly fees=360×720+480×1280=873600

Question 4 |

Rubina decided to donate 16%ofher monthly salary to an NGO. On the day of donation she changed her mind and donated Rs. 6,567 which was 75% of what she had decided earlier. How much is Rubina's monthly salary ?

Rs. 8756 | |

Rs. 54725 | |

Rs. 6,56.,700 | |

Rs. 45,696 |

Question 4 Explanation:

Let his salary be p

Initial decision to donate=16/100×p=0.16p

Final decision=0.16p×.75

Thus,0.16p×0.75=6567

p=54725

Initial decision to donate=16/100×p=0.16p

Final decision=0.16p×.75

Thus,0.16p×0.75=6567

p=54725

Question 5 |

Six-eleventh of a number is equal to twenty two percent of second number. Second number is equal to the one-fourth of third number. The value of the third number is 2400, What is the 45% of first number?

107.6 | |

131.1 | |

115.4 | |

None |

Question 5 Explanation:

Let the numbers are a,b,c

Now according to the question

6a/11 = 22b/100 ……….(1)

And b = c/4…………………(2)

We are also given by the value of c i.e. 2400

So the value of b would be 600

Now put b = 600 in equation 1

6a/11 = (22 x 600)/100

6a/11= 132

a = 242

Now 45% of 242 = 108.9

Now according to the question

6a/11 = 22b/100 ……….(1)

And b = c/4…………………(2)

We are also given by the value of c i.e. 2400

So the value of b would be 600

Now put b = 600 in equation 1

6a/11 = (22 x 600)/100

6a/11= 132

a = 242

Now 45% of 242 = 108.9

Once you are finished, click the button below. Any items you have not completed will be marked incorrect.

There are 5 questions to complete.

List |