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## Arithmetic: Profit and Loss Test -6

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*Arithmetic: Profit and Loss Test -6*.You scored %%SCORE%% out of %%TOTAL%%.You correct answer percentage: %%PERCENTAGE%% .Your performance has been rated as %%RATING%% Your answers are highlighted below.

Question 1 |

A man invested Rs. 8000 for a year in the share market. At the end of the year, he gained 15% and he invested the amount with profit again for the second year. At the end of the second year, he suffered a loss of 15%. Find the gain or loss per cent in the investment after two years.

Gain 3.25% | |

Loss 2.25% | |

No loss no gain | |

Loss 5% |

Question 1 Explanation:

If we see the question we can say that

Amount after one year with 15% gain = 8000 x 115/100= Rs 9200

Again with a loss of 15% then

Amount after 2nd yr = 9200 x 85/100 = 7820

Therefore

Loss per cent

= (8000 -7820)/8000 x 100 = 2.25%

Amount after one year with 15% gain = 8000 x 115/100= Rs 9200

Again with a loss of 15% then

Amount after 2nd yr = 9200 x 85/100 = 7820

Therefore

Loss per cent

= (8000 -7820)/8000 x 100 = 2.25%

Question 2 |

By selling an article at 80% of its marked price, Meera makes a loss of 12%. What will be the percent profit or loss made by the Meera if she sells the article at 95% of its marked price?

5.5% profit | |

1% loss | |

5% profit | |

4.5% profit |

Question 2 Explanation:

Let the cost price =Rs p.

Since the article is sold at 80% of its marked price so

Selling price = 0.88 p

therefore Marked price of article

= 0.88/80 x100 x p=1.1p

= New selling price of article = 1.045p

= {(1.045x – p)/p} x 100= 4.5%

Since the article is sold at 80% of its marked price so

Selling price = 0.88 p

therefore Marked price of article

= 0.88/80 x100 x p=1.1p

= New selling price of article = 1.045p

= {(1.045x – p)/p} x 100= 4.5%

Question 3 |

What is the maximum percentage discount that a merchant can offer on her marked price so that she ends up selling at no profit or loss, if she had initially marked her goods up by 50%?

16.67% | |

33.33% | |

50% | |

20% |

Question 3 Explanation:

Let cost price = Rs 100

Marked price = Rs 150 (50% initially she had)

So maximum discount percentage is = 50/150 x 100 = 33.33%

Marked price = Rs 150 (50% initially she had)

So maximum discount percentage is = 50/150 x 100 = 33.33%

Question 4 |

A tradesman gives 4% discount on the marked price and 1 article free with every 15 articles still gains 35%. The marked price is more than cost price by?

40% | |

39% | |

20% | |

50% |

Question 4 Explanation:

Let the C.P of each article be Rs p

Then C.P of 16 articles=Rs (px16) =Rs 16p

S.P of 15 articles =16p x (135/100)=Rs 21.6

S.P of each article =21.6/15=Rs 1.44

When S.P is Rs 0.96(after 4%discount), marked price =Rs p

And S.P is Rs 1.44, marked price = (p/0.96p)x1.44=Rs 1.5p

Therefore marked price=50%

Then C.P of 16 articles=Rs (px16) =Rs 16p

S.P of 15 articles =16p x (135/100)=Rs 21.6

S.P of each article =21.6/15=Rs 1.44

When S.P is Rs 0.96(after 4%discount), marked price =Rs p

And S.P is Rs 1.44, marked price = (p/0.96p)x1.44=Rs 1.5p

Therefore marked price=50%

Question 5 |

Even after reducing the marked price of pen by Rs. 32, a shopkeeper makes a profit of 15%. If the cost price be Rs320, what percentage of profit does he make if he sells the pen at the marked price?

25% | |

20% | |

10% | |

30% |

Question 5 Explanation:

Profit percentage ={ (Selling price – Cost price)/(cost price)} x 100

Profit = 1.15

Therefore selling price

= 1.15 x 320 = Rs 368

But SP = MP - 32

So, MP = SP + 32 = 368 + 32 = Rs 400

so profit percentage=[{ 400 – 320}/320]x 100 = 25%

Profit = 1.15

Therefore selling price

= 1.15 x 320 = Rs 368

But SP = MP - 32

So, MP = SP + 32 = 368 + 32 = Rs 400

so profit percentage=[{ 400 – 320}/320]x 100 = 25%

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