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Arithmetic: Ratio and Proportion Test-3

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Question 1
A sum of money is divided among A. B. C and D in the ratio of 3 : 4 : 9 : 10 respectively. If the share of C is Rs.2.580 more than the share of B. then what is the total amount of money of A and D has together?
A
Rs.5.676
B
Rs.6.192
C
Rs.6.708
D
Rs.7.224
Question 1 Explanation: 
Let the common ratio be x As share=3x Bs share=4x Cs share=9x Ds share=10x Given, 9x-4x=2.580 X=0.516 So 13x=6.708
Question 2
Number of students in Arts and Science faculties in an institute are in the ratio of 5: 8 respectively. If 150 more students join Art faculty while 80 more students join Science faculty, the respective ratio becomes 3: 4. Originally what was the total number of students in both faculties together?
A
1200
B
1400
C
1150
D
none
Question 2 Explanation: 
Let the original common ratio be x
Students in art=5x
Student in science=8x
So,(5x+150)/(8x+80)=3/4
x=90
Original strength 13x=1170
Question 3
The angles of a quadrilateral are in the ratio of 2 : 4 : 7 : 5. The smallest angle of the quadrilateral is equal to the smallest angle of a triangle. One of the angles of the triangle is twice the smallest angle of the triangle. What is the second largest angle of the triangle?
A
80°
B
60°
C
120°
D
Cannot be determined
Question 3 Explanation: 
Let the common ratio of the angles of quadrilateral be x
Smallest angle=2x
Also, 2x+4x+7x+5x=360
X=20
So the two angles of triangle are 40 and 80
The third angle=180-120=60
So the second largest angle=60
Question 4
The ratio between the angles of a quadrilateral is 3 : 4 : 6 : 7. Half the second largest angle of the quadrilateral is equal to the smaller angle of a parallelogram. What is the value of adjacent angle of the parallelogram?
A
136°
B
126°
C
94°
D
96°
Question 4 Explanation: 
Let the common ratio of the angles of quadrilateral be x
Second largest angle=6x
Also, 3x+4x+6x+7x=360
X=18
Thus,6x=108
Given angle of parallelogram=54
As the sum of adjacent angles of parallelogram is 180
Adjacent angles value is 180-54=126
Question 5
Mr. Pandit owned 950 gold coins all of which he distributed amongst his three daughters Lalita, Amita and Neeta. Lalita gave 25 gold coins to her husband, Amita donated 15 gold coins and Neeta made jewellery out of 30 gold coins. The new respective ratio of the coins left with them was 20: 73: 83. How' many gold coins did Amita receive from Mr. Pandit?
A
380
B
415
C
400
D
350
Question 5 Explanation: 
Let the common ratio of coins left with all be x Coins left with Lalita=20x Coins left with Amita=73x Coins left with Neeta=83x Originally, coins received by lalita=20x+25 Originally, coins received by Amita=73x+15 Originally, coins received by Neeta=83x+30 As total coins =950 20x+25+73x+15+83x+30=950 X=5 Therefore number of coins got by Amita=380
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