- This is an assessment test.
- These tests focus on the basics of Maths and are meant to indicate your preparation level for the subject.
- Kindly take the tests in this series with a pre-defined schedule.
Basic Maths: Test 12
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Your answers are highlighted below.
Question 1 |
$ \displaystyle 10-\left[ 4-\left\{ 3-\left( 3-3-6 \right) \right\} \right]$ is equal to:
15 | |
16 | |
14 | |
10 |
Question 1 Explanation:
$ \displaystyle \begin{array}{l}p=10-\left[ 4-\left\{ 3-\left( 3-3-6 \right) \right\} \right]\\=10-\left[ 4-\left\{ 3-\left( -6 \right) \right\} \right]\\=10-\left[ 4-\left\{ 3+6 \right\} \right]\\=10-\left[ 4-9 \right]\\=10+5=15\end{array}$
Question 2 |
Evaluate:$ \displaystyle \frac{-{{\left( 4-6 \right)}^{2}}-3\left( -2 \right)+6}{17-9\div 3\times 5}$
$ \displaystyle \frac{3}{8}$ | |
$ \displaystyle 7$ | |
$ \displaystyle 4$ | |
$ \displaystyle \frac{7}{4}$ |
Question 2 Explanation:
$ \displaystyle \begin{array}{l}?=\frac{-{{\left( -2 \right)}^{2}}+6+6}{17-15}\\=\frac{-4+12}{2}=\frac{8}{2}=4\end{array}$
Question 3 |
Simplify: $ \displaystyle \frac{\frac{5}{3}\times \frac{7}{51}of\,\frac{17}{5}-\frac{2}{3}}{\frac{2}{9}\times \frac{5}{7}of\,\frac{28}{5}-\frac{1}{3}}$
$ \displaystyle \frac{1}{2}$ | |
$ \displaystyle 4$ | |
$ \displaystyle \frac{1}{5}$ | |
$ \displaystyle \frac{1}{4}$ |
Question 3 Explanation:
Question 4 |
$ \displaystyle 3-\left[ 5-\left\{ 2+\left( -5+6-2 \right)2 \right\} \right]$ is equal to
-4 | |
2 | |
0 | |
-2 |
Question 4 Explanation:
$ \displaystyle \begin{array}{l}p=3-\left[ 5-\left\{ 2+\left( -1 \right)2 \right\} \right]\\=3\times \left[ 5-\left\{ 2-2 \right\} \right]\\=3-\left[ 5-0 \right]\\=3-5=-2\end{array}$
Question 5 |
On simplification 2134−(1002/20.04) is equal to:
3029 | |
2084 | |
2993 | |
2543 |
Question 5 Explanation:
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