- This is an assessment test.
- These tests focus on the basics of Maths and are meant to indicate your preparation level for the subject.
- Kindly take the tests in this series with a pre-defined schedule.
Basic Maths: Test 16
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Question 1 |
$ \displaystyle {{\left( 100 \right)}^{\frac{1}{2}}}\times {{\left( 0.001 \right)}^{\frac{1}{3}}}-{{\left( 0.0016 \right)}^{\frac{1}{4}}}\times {{3}^{0}}+{{\left( \frac{1}{2} \right)}^{-1}}$ is equal to
2.8 | |
1.8 | |
1.0 | |
0 |
Question 1 Explanation:
$ \displaystyle \begin{array}{l}{{\left( 100 \right)}^{\frac{1}{2}}}\times {{\left( 0.001 \right)}^{\frac{1}{3}}}-{{\left( 0.0016 \right)}^{\frac{1}{4}}}\times {{3}^{0}}+{{\left( \frac{1}{2} \right)}^{-1}}\\=10\times 0.1-0.2\times 1+2\\=1-0.2+2=2.8\end{array}$
Question 2 |
The vale of $ \displaystyle 28-5\left[ 2+3\left( 2-2\left( 5-3 \right)+5 \right)-10 \right]\div 4$ is
5 | |
23.25 | |
26.75 | |
25 |
Question 2 Explanation:
Question 3 |
$ \displaystyle 2-1\,\frac{2}{9}\,\,of\,3\frac{3}{11}\div 5\frac{1}{7}\,\,of\,\,\frac{7}{9}\,\,\,$ is equal to
$ \displaystyle 1$ | |
$ \displaystyle 9$ | |
$ \displaystyle 8\frac{32}{81}$ | |
$ \displaystyle \frac{3}{4}$ |
Question 3 Explanation:
Expression $ \displaystyle \begin{array}{l}=2-\frac{11}{9}\,\,of\,\frac{36}{11}\div \frac{36}{7}\,\,of\,\,\frac{7}{9}\,\,\,\\2-\frac{11}{9}\times \frac{36}{11}\div \frac{36}{7}\times \frac{7}{9}\\=2-4\div 4\\=2-4\times \frac{1}{4}=2-1=1\end{array}$
Question 4 |
The value of $ \displaystyle \frac{5}{1\frac{7}{8}\,of\,1\frac{1}{3}}\times \frac{2\frac{1}{10}}{3\frac{1}{2}}\,\,of\,\,2\frac{1}{4}$
$ \displaystyle 2\frac{7}{10}$ | |
$ \displaystyle 0.5$ | |
$ \displaystyle 1$ | |
$ \displaystyle 2$ |
Question 4 Explanation:
$ \displaystyle \begin{array}{l}\frac{5}{\frac{15}{8}\times \frac{4}{3}}\times \frac{\frac{21}{10}}{\frac{7}{2}}\,of\,\frac{9}{4}\\=5\times \frac{2}{5}\times \frac{21}{10}\times \frac{2}{7}\times \frac{9}{4}\\=\frac{27}{10}=2\frac{7}{10}\end{array}$
Question 5 |
$ \displaystyle if\,\,\frac{1520}{\sqrt{p}}=80$ the value of p
14 | |
140 | |
361 | |
225 |
Question 5 Explanation:
$ \displaystyle \begin{array}{l}80\times \sqrt{p}=1520\\\Rightarrow \sqrt{p}=\frac{1520}{80}=19\\\Rightarrow p={{\left( 19 \right)}^{2}}=361\end{array}$
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