Basic Maths: Test 4

This is an assessment test.
These tests focus on the basics of Maths and are meant to indicate your preparation level for the subject.
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Question 1

54.5% of 600 + 30.5% of 1800 = (p)²+200

A	+36 or -36
B	+26 or -26
C	–81 or +81
D	none

Question 1 Explanation:

$ \displaystyle \begin{array}{l}\frac{54.5\times 600}{100}+\frac{30.5\times 1800}{100}={{p}^{2}}+200\\\Rightarrow 327+549={{p}^{2}}+200\\\Rightarrow 876={{p}^{2}}+200\\\Rightarrow {{p}^{2}}=876-200=676\\Therefore\,\,p=\sqrt{676}=\pm 26\end{array}$

Question 2

$ \displaystyle \sqrt{{{7}^{2}}\times 6+\left( {{15}^{2}} \right)+57}=p$

A	24
B	(519)^1/2
C	519
D	529

Question 2 Explanation:

$ \displaystyle \begin{array}{l}p=\sqrt{49\times 6+225+57}\\=\sqrt{294+225+57}\\=\sqrt{576}=24\end{array}$

Question 3

Find the value of p? $ \displaystyle \sqrt{625.04}\times 16.94+204.001\div 17=p$

A	4.18
B	4.41
C	425
D	437

Question 3 Explanation:

Taking approximate values
$ \displaystyle \begin{array}{l}p=\sqrt{625}\times 17+204\div 17\\=25\times 17+204\times \frac{1}{17}\\=425+12=437\end{array}$

Question 4

$ \displaystyle 0.34\overline{33}+0.13\overline{33}=?$

A	$ \displaystyle 0.47$
B	$ \displaystyle 0.47\overline{66}$
C	$ \displaystyle 0.\overline{48}$
D	$ \displaystyle 4.\overline{8}$

Question 4 Explanation:

$ \displaystyle \begin{array}{l}0.34\overline{33}+0.13\overline{33}\\=\frac{3433-34}{9900}+\frac{1333-13}{9900}\\=\frac{3399+1320}{9900}=\frac{4719}{9900}\\=\frac{4766-47}{9900}=0.47\overline{66}\end{array}$

Question 5

28.217 – 14.241 + 6.873 – 2.434 =p