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Geometry and Mensuration: Level 1 Test 10
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Question 1 |
The length and breadth of a playground are 36 m and 21 m respectively. Poles are required to be fixed all along the boundary at a distance 3 m apart. The number of poles required will be
39 | |
38 | |
37 | |
40 |
Question 1 Explanation:
$\displaystyle \begin{array}{l}The\text{ }total\text{ }number\text{ }of\text{ }the\text{ }poles\text{ }=\\\frac{36}{3}+1+\frac{21}{3}+1+\frac{21}{3}-1+\frac{36}{3}-1\\=\,12+1+7+1+7+12-1-1=38\end{array}$
Question 2 |
. The perimeters of a square and a regular hexagon are equal. The ratio of the area of the hexagon to the area of the square is
2√3: 3 | |
√3: 1 | |
3√3: 2 | |
√2 : 3 |
Question 2 Explanation:
Let the perimeter be 24 cm.
Thus the area of the square = (24/4)2 =36 cm2
The side of the hexagon = 24/6 cm=4 cm.
There are 6 equilateral triangles in the hexagon.
Each equilateral triangle = (√3/4)x42 =4√3 cm2
Thus the total area of hexagon = 24√3 cm2 =24√3
The required ratio =24√3 : 36 = 2√3 : 3
Thus the area of the square = (24/4)2 =36 cm2
The side of the hexagon = 24/6 cm=4 cm.
There are 6 equilateral triangles in the hexagon.
Each equilateral triangle = (√3/4)x42 =4√3 cm2
Thus the total area of hexagon = 24√3 cm2 =24√3
The required ratio =24√3 : 36 = 2√3 : 3
Question 3 |
A rectangular piece of cardboard 18 cm x 24 cm is made into an open box by cutting a square of 5 cm side from each corner and build up the side. Find the volume of the box.
432 cu cm | |
560 cu cm | |
216 cu cm | |
None of these |
Question 3 Explanation:
The volume of the box is
(18-2x5)(24-2x5)(5) = 560 cu m.
Correct option is (b)
(18-2x5)(24-2x5)(5) = 560 cu m.
Correct option is (b)
Question 4 |
The locus of a point equidistant from the two fixed points is
Any straight line bisecting the segment joining the fixed points | |
Any straight line perpendicular to the segment joining the fixed points | |
The straight line which is perpendicular bisector of the segments joining the fixed points | |
Any straight line perpendicular to the line joining the fixed points |
Question 5 |
Any cyclic parallelogram having unequal adjacent sides is necessarily a
Square | |
Rectangle | |
Rhombus | |
Trapezium |
Question 5 Explanation:
A cyclic quadrilateral has the sum of diagonally opposite angles = 180o
The diagonally opposite angles in a parallelogram are equal.
Thus the angles of the cyclic parallelogram = 90o
The cyclic parallelogram is necessarily a rectangle.
The diagonally opposite angles in a parallelogram are equal.
Thus the angles of the cyclic parallelogram = 90o
The cyclic parallelogram is necessarily a rectangle.
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