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Number System: Exponent Test-1
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Question 1 |
(68-67)(69-68)=?
36 | |
62 | |
25 x 615 | |
5 x 615 |
Question 1 Explanation:
Using BODMAS and taking out the common powers from the bracket,
we are left with:
67(6-1)68(6-1)
6768(6-1) (6-1)
615 x 5 x 5
25 x 615
we are left with:
67(6-1)68(6-1)
6768(6-1) (6-1)
615 x 5 x 5
25 x 615
Question 2 |
What is the value of x if 810x-4 = 642x+4
1 | |
2 | |
3 | |
4 |
Question 2 Explanation:
Since the bases of the two sides are not equal, we first equate the bases.
We know 82=64
Therefore,
642x+4 = 8 2( 2x+4) = 8 4x+8
Now let’s change our original equation:
810x-4= 642x+4
810x-4= 8 4x+8
Thus, 10x -4 = 4x + 8
6x = 12
x = 2
We know 82=64
Therefore,
642x+4 = 8 2( 2x+4) = 8 4x+8
Now let’s change our original equation:
810x-4= 642x+4
810x-4= 8 4x+8
Thus, 10x -4 = 4x + 8
6x = 12
x = 2
Question 3 |
What’s the largest value for x, so that 3x is a factor of 5412?
6 | |
12 | |
24 | |
36 |
Question 3 Explanation:
$ \begin{array}{l}Let\,us\,reduce\,the\,number\,{{54}^{{12}}}\operatorname{int}o\,\,factors\,\,of\,\,3\\{{54}^{{12}}}={{(2\times 27)}^{{12}}}\\={{(2\times 9\times 3)}^{{12}}}\\=\,\,{{(2\times 3\times 3\times 3)}^{{12}}}\\=\,\,({{2}^{{12}}}{{3}^{{12}}}{{3}^{{12}}}{{3}^{{12}}})\\=\,\,{{2}^{{12}}}{{3}^{{36}}}\end{array}$
Question 4 |
What is the value of 6.12 x 109?
0.00000000612 | |
0.000000612 | |
6.12 | |
6120000000 |
Question 4 Explanation:
This is a simple problem.
The number effectively becomes 612 x 107
. All you need to do is place seven zeros after the two.
The number effectively becomes 612 x 107
. All you need to do is place seven zeros after the two.
Question 5 |
128146225/2253776115 = ?
2 | |
3 | |
6 | |
12 |
Question 5 Explanation:
The numerator reduces to:
2273876115
Dividing by
2253776115,
we obtain 2231, thus the correct answer is option D.
2273876115
Dividing by
2253776115,
we obtain 2231, thus the correct answer is option D.
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