Deepinder’s age is 1/6th of her father’s age. Deepinde’s father’s age will be twice the age of Maninder’s age after 10 years. If Maninder’s eight birthdays was celebrated two years before, then what is Deepinder’s present age.

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Consider Deepinder’s present age to be = x Then her father’s age is = 6x

It is given that Deepinder ‘s father’s age will be twice the age of Maninder’s age after 10 years Maninder’s age after 10 years = ½(6x + 10) = 3x + 5

Also given that Maninder’s eight birthdays was celebrated two years before. Maninder’s age after 10 years = 8 + 12 = 20

3x + 5 = 20 x = 15/3 = 5

Deepinder ‘s present age = 5 years


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