Select Page

• This is an assessment test.
• To draw maximum benefit, study the concepts for the topic concerned.
• Kindly take the tests in this series with a pre-defined schedule.

## Algebra: Basics Test-3

Congratulations - you have completed Algebra: Basics Test-3.You scored %%SCORE%% out of %%TOTAL%%.You correct answer percentage: %%PERCENTAGE%% .Your performance has been rated as %%RATING%%
 Question 1
$\displaystyle if\,\,\,\frac{a}{3}=\frac{b}{4}=\frac{c}{7}\,\,then\,\,\frac{a+b+c}{c}\,\,is\,\,equal\,\,\,to:$
 A 2 B 4 C 6 D 7
Question 1 Explanation:
$\displaystyle \begin{array}{l}\frac{a}{3}=\frac{b}{4}=\frac{c}{7}=1\,(let)\\a=3k,\,=4k\,,c=7k\\\therefore \frac{a+b+c}{c}=\frac{3k+4k+7k}{7k}\\=\frac{14k}{7k}=2\end{array}$
 Question 2
$\displaystyle f\,\,\frac{144}{0.144}=\frac{14.4}{p}$,then the value of p is
 A 144 B 0.0144 C 1.44 D 14.4
Question 2 Explanation:
$\displaystyle \begin{array}{l}\frac{144}{0.144}=\frac{14.4}{p}\\\Rightarrow 144\times p=14.4\times 0.144\\\Rightarrow p=\frac{14.4\times 0.144}{144}\\=\frac{144\times 144}{144\times 10000}=0.0144\end{array}$
 Question 3
If 1 < c < 2, then the value of
$\displaystyle \sqrt{{{\left( c-1 \right)}^{2}}}\,+\sqrt{{{\left( c-3 \right)}^{2}}}\,$ is
 A 3 B 2x−4 C 1 D 2
Question 3 Explanation:
Since 1< c < 2, we have
c−1 > 0 and
c−3 < 0
or, 3 –c > 0
$\displaystyle \therefore \sqrt{{{\left( c-1 \right)}^{2}}}+\sqrt{{{\left( 3-c \right)}^{2}}}\,$
$\displaystyle \begin{array}{l}=\sqrt{{{\left( c-1 \right)}^{2}}}\,+\sqrt{{{\left( 3-c \right)}^{2}}}\\\left[ \because \,{{\left( c-3 \right)}^{2}}={{\left( 3-c \right)}^{2}}\, \right]\\=c-1+3-c=2\end{array}$
 Question 4
p x q = (p × q) +q, then 5 x 7 equals to
 A 40 B 42 C 30 D 32
Question 4 Explanation:
$\displaystyle \begin{array}{l}p\times r=\left( p\times q \right)+q\\\therefore 5\times 7=\left( 5\times 7 \right)+7=35+7=42\end{array}$
 Question 5
If f = 0.1039, then the value of $\displaystyle \sqrt{4{{f}^{2}}-4f+1\,\,}\,$ +3f is
 A 1.1039 B 2.1039 C 0.1039 D 0.2078
Question 5 Explanation:
f= 0.1039 (given)
$\displaystyle \begin{array}{l}Now,\,\sqrt{4{{f}^{2}}-4f+1+3f}\,\\=\sqrt{{{\left( 1-2f \right)}^{2}}}\,+3f\\=1-2f+3f\\=1+f=1+0.1039\\=1.1039\end{array}$
Once you are finished, click the button below. Any items you have not completed will be marked incorrect.
There are 5 questions to complete.
 ← List →
Shaded items are complete.
 1 2 3 4 5 End