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Algebra: Functions Test-5

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 Question 1
If x and y are real numbers, the functions are defined as f(x, y) = I x + Y I, F (x, y) = - f (x, y) and G (x, y) = - F (x, y). Now with the help of this information answer the following questions: If Y = which of the following will give x2 as the final value
 A f(x, y) G (x, y) 4 B G (f (x, y)f(x, y)) F (x, y)/8 C - F (x, y) G (x, y)/log216 D – f(x, y) G (x, y) F (x, y)/F (3x, 3y)
Question 1 Explanation:
$\displaystyle \begin{array}{l}-F\,\left( x,\,\,y \right)\,.\,G\,\left( x,y \right)=-\left[ -\left| \,\,\,\,x+y\,\,\, \right|\,\,\,\,.\,\,\,\,\left| \,\,\,x+y\,\,\, \right|\,\, \right]\\\frac{-\left( -2x.2x \right)}{{{\log }_{2}}16}=4{{x}^{2}}\,\,\,\,\,\,\because \,[{{\log }_{2}}16={{\log }_{2}}{{2}^{4}}=4]\\therefore\,\,option\,\,c\,\,is\,\,the\,\,right\,\,answer\end{array}$
 Question 2
Using the relation answer the questions given below @ (A, B) = average of A and B /(A, B) = product of A and B, x (A, B) = the result when A is divided by B The sum of A and B is given by
 A \ (@ (A, B), 2) B @ ( \ (A, B), 2) C @ (X (A, B), 2) D none of these
Question 2 Explanation:
Going through the various options
$\backslash \left( \left( A,B \right),2 \right)=\backslash \left( \frac{A+B}{2},2 \right)=\frac{A+B}{2}\times 2=A+B$
 Question 3
Using the relation answer the questions given below @ (A, B) = average of A and B /(A, B) = product of A and B, x (A, B) = the result when A is divided by B The average of A, Band C is given by
 A @ (x (\ (@ (A, B), 2), C), 3) B \ (x (\ (@ (A, B)), C 2)) C X (@ (\ (@ (A, B), 2), C,3)) D X (\ (@ (\ (@ (A, B), 2), C), 2), 3)
Question 3 Explanation:
$\displaystyle \begin{array}{l}(a)\,\,\text{ }\left( x\text{ }\left( \backslash \text{ }\left( \text{ }\left( A,\text{ }B \right),\text{ }2 \right),\text{ }C \right),\text{ }3 \right)=\text{ }\text{ }(x\text{ }(\backslash \left( \frac{A+B}{2},2 \right),C),\text{ }3)\\=\text{ }\left( x\text{ }\left( A+B,\text{ }C \right),\text{ }3 \right)\\=\left( \frac{A+B}{C},3 \right)\\\left( b \right)\text{ }\backslash \text{ }\left( x\text{ }\left( \backslash \text{ }\left( \text{ }\left( A,\text{ }B \right) \right),\text{ }C\text{ }2 \right) \right)\\=\text{ }\!\!\backslash\!\!\text{ }\left( x\left( \backslash \left( \frac{A+B}{2},C\,2 \right) \right) \right)\\=\backslash \left( x\left( \frac{A+B}{2}\times C\,2 \right) \right)\\(c)X\left( \left( \backslash \left( \left( A,B \right),2 \right),C,3 \right) \right)\\=X\left( \left( \backslash \left( \frac{A+B}{2},2 \right),C,3 \right) \right)\\=X\left( \left( A+B,C,3 \right) \right)\\=X\left( \frac{A+B+C}{2},3 \right)=\frac{A+B+C}{6}\\(d)\,X\left( \backslash \left( \left( \backslash \left( \left( A,B \right),2 \right),C \right),2 \right),3 \right)\\=X\left( \backslash \left( \left( \backslash \left( \left( A,B \right),2 \right),C \right),2 \right),3 \right)\\=X\left( \backslash \left( \left( \backslash \left( \frac{A+B}{2},2 \right),C \right),2 \right),3 \right)\\=X\left( \backslash \left( \left( A+B,C \right),2 \right),3 \right)\\=X\left( \backslash \left( \frac{A+B+C}{2},2 \right),3 \right)\\=X\left( \backslash \left( A+B+C,3 \right) \right)=\frac{A+B+C}{3}\end{array}$
 Question 4
x and yare non-zero real numbers f (x, y) = + (x +y)0.5,if (x +y)0.5is real otherwise = (x +y)2 g (x, y) = (x +y)2 if (x + y)0.5is real, otherwise =- (x +y) For  which of the following is f (x, y) necessarily greater than g (x, y)option
 A x and y are positive B x and y are negative C x and y are greater than - 1 D None of these
Question 4 Explanation:
When both x and y are positive
f (x, y) = + (x +y)0.5g (x, y) = (x +y)2 so g(x,y)>f(x,y)
When both x and y are negative
f(x, y) = (x +y)2g (x, y) = -(x +y)
If   x+y>-1
g(x,y)>f(x,y)
When x and y are greater than -1. They can be both positive as well as in the range 0 to -1
so both a and b option cases arise.
 Question 5
x and yare non-zero real numbers f (x, y) = + (x +y)0.5,if (x +y)0.5is real otherwise = (x +y)2 g (x, y) = (x +y)2 if (x + y)0.5is real, otherwise =- (x +y) Which of the following is necessarily false?
 A f(x,y) >g(x,y) for 0 B f(x,y) > g (x,y) when x,y<-1 C f (x, y) > g (x, y) for x, y > 1 D None of these
Question 5 Explanation:
In this case ,f (x, y) = + (x +y)0.5    g (x, y) = (x +y)2
This is true cause (x+y)<1 for which  (x +y)0.5>(x +y)2
In this case, f(x, y) = (x +y)2      g (x, y) = -(x +y)
This is also true cause for (x+y)<-2  (x +y)2>-(x+y)
In this case f (x, y) = + (x +y)0.5    g (x, y) = (x +y)2
This is false because for(x+y)>2 (x +y)2>(x +y)0.5
So the answer is c
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