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## Algebra: Functions Test-6

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 Question 1
x and y are non-zero real numbers
f (x, y) = + (x +y)0.5,if (x +y)0.5is real otherwise = (x +y)2
g (x, y) = (x +y)2 if (x + y)0.5is real, otherwise =- (x +y)
If f(x, y) =g (x, y) then
 A x=y B x+y= 1 C x+y=-2 D Both b and c
Question 1 Explanation:
Going through all the options
The value of x and y could be anything so cant be sure about the functions
In this case ,f (x, y) = + (x +y)0.5    g (x, y) = (x +y)2
In this case both are 1
So f(x, y) =g (x, y)
 Question 2
 A y=ax+b B y=a+bx+cx2 C y=eax+b D None of these
Question 2 Explanation:
(a) Can be eliminated as looking at the data we can conclude that there is no linear relation between x and y
(b) Using the various values of x and y we can create the following equations
4=a+b+c -----------(1)
6=a+2b+4c---------(2)
14=a+3b+9c--------(3)
22=a+4b+16c
32=a+5b+25c
44=a+6b+36c
We will find the values of a,b and c using the first 3 equations and will check if the values satisfy the other 3 equations
Using eq 1 and 2 we get
2=b+3c
Using 2 and 3 we get
8=b+5c
Solving we get c=3,b=-7 and a=8
The values of a, b and c satisfy all the equations to a large limit.
(c) As the exponential function grows more quickly for small positive values as compared to large values,
while quite the opposite is happening here. So can’t be a match
 Question 3
If f(0, y) = y + 1, and f(x + I, y) =f (x, f (x, y)). Then, what is the value of f(1,2) ?
 A 1 B 2 C 3 D 4
Question 3 Explanation:
F(1,2)=f(0,3) F(0,3)=4 So,f(1,2)=4
 Question 4
Functions m and M are defined as follows: m (a, b, c) = min (a + b, c, a) M(a, b, c) = max (a + b, c, a) If a = - 2, b = - 3 and c = 2 what is the maximum between $\displaystyle \left[ \frac{m\text{ }\left( a,\text{ }b,\text{ }c \right)+M\text{ }\left( a,\text{ }b,\text{ }c \right)}{2} \right]and\left[ \frac{m\text{ }\left( a,\text{ }b,\text{ }c \right)\text{ }M\text{ }\left( a,\text{ }b,\text{ }c \right)}{2} \right]$
 A 3/2 B 7/2 C -3/2 D -7/2
Question 4 Explanation:
[m (a, b, c)+M (a, b, c)]/2=-3/2 [m (a, b, c) –M (a, b, c)]/2=-7/2 Max of the 2 is -3/2 which is the answer
 Question 5
Functions m and M are defined as follows: m (a, b, c) = min (a + b, c, a) M(a, b, c) = max (a + b, c, a) If a  b, and c are negative, then what gives the minimum of a and b
 A m (a,b,c) B –M (-a, a,-b) C m (a+b, b,c) D None of these
Question 5 Explanation:
As all a,b and c are negative
(a)    m (a,b,c)=min(a+b,c,a)
(b)   –M (-a, a,-b)=-max(0,-b,-a)
(c)    m (a+b, b,c)=min(a+2b,c,a+b)
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