• This is an assessment test.
  • To draw maximum benefit, study the concepts for the topic concerned.
  • Kindly take the tests in this series with a pre-defined schedule.

Algebra: Quadratic Equations Test-3

Congratulations - you have completed Algebra: Quadratic Equations Test-3. You scored %%SCORE%% out of %%TOTAL%%. You correct answer percentage: %%PERCENTAGE%% . Your performance has been rated as %%RATING%%
Your answers are highlighted below.
Question 1
Which of the following is a quadratic equation?
A
$ \displaystyle {{x}^{\frac{1}{2}}}+2x+3=0$
B
$ \displaystyle \left( x-1 \right)\,\left( x+4 \right)={{x}^{2}}+1$
C
$ \displaystyle {{x}^{4}}-3x+5=0$
D
$ \displaystyle \left( 2x+1 \right)\,\left( 3x-4 \right)\,=2{{x}^{2}}+3$
Question 1 Explanation: 
By observation the highest power of x is 2 only in option (d)
Question 2
Which one of the following is a factor of
$ \displaystyle {{x}^{3}}-19x+30$
A
$ \displaystyle x-2$
B
$ \displaystyle x+2$
C
$ \displaystyle x-1$
D
$ \displaystyle x+1$
Question 2 Explanation: 
Capture
Thus, x-2 is one of the factors.
Question 3
The solution of the equation
$ \displaystyle \sqrt{25-{{x}^{2}}}=x-1$ are
A
$ \displaystyle x=3\,\,\,and\,\,x=4$
B
$ \displaystyle x=5\,\,\,\,and\,\,\,\,x=1$
C
$ \displaystyle x=-3\,\,and\,\,x=4$
D
$ \displaystyle x=4\,\,\,\,and\,\,\,x\ne -3$
Question 3 Explanation: 
For x =4 , the equation
$latex \sqrt{25-{{x}^{2}}}=x-1$ is satisfied ,
Thus options which can be correct are a, c and d. Now when we put x=-3 we find that both sides are not equal so we can conclude that (d) is the answer)
Question 4
Of the following quadratic equations
which is the one whose roots are 2 and −15?
A
$ \displaystyle {{x}^{2}}-2x+15=0$
B
$ \displaystyle {{x}^{2}}+15x-2=0$
C
$ \displaystyle {{x}^{2}}+13x-30=0$
D
$ \displaystyle {{x}^{2}}-30=0$
Question 4 Explanation: 
The factors are x-2 and x+15.
Thus the quadratic equation is
$ \begin{array}{l}(x-2)(x+15)\\={{x}^{2}}+13x-30\end{array}$
Question 5
If $ \displaystyle \begin{array}{l}{{\left( a-3 \right)}^{2}}+{{\left( b-4 \right)}^{2}}+{{\left( c-9 \right)}^{2}}=0,\,\,\\then\,\,the\,\,value\,\,of\,\,\sqrt{a+b+c}\end{array}$ is
A
-4
B
+4
C
±4
D
±2
Question 5 Explanation: 
Since the sum of three squares can only be equal to 0
if the terms are individually equal to 0
we can conclude that a=3,b=4,c=9.
The sum of a, b, c = 16.
Thus, $ \sqrt{a+b+c}=\sqrt{16}=\pm 4$
Once you are finished, click the button below. Any items you have not completed will be marked incorrect. Get Results
There are 5 questions to complete.
List
Return
Shaded items are complete.
12345
End
Return

Want to explore more Arithmetic Tests?

Explore Our Arithmetic Tests

Get Posts Like This Sent to your Email
Updates for Free Live sessions and offers are sent on mail. Don't worry: we do not send too many emails..:)
Get Posts Like This Sent to your Email
Updates for Free Live sessions and offers are sent on mail. Don't worry: we do not send too many emails..:)



Join Our Newsletter
Get the latest updates from our side, including offers and free live updates, on email.
Join Our Newsletter
Leverage agile frameworks to provide a robust synopsis for high level overviews.
4 Short Term Courses launched for CAT-2021. Special 10% off as launch offer.
10
days
10
hours
10
minutes
10
seconds
4 Short Term Courses launched for CAT-2021. Special 10% off as launch offer.
10
days
10
hours
10
minutes
10
seconds
Join our Free TELEGRAM GROUP for exclusive content and updates
Join our Free TELEGRAM GROUP for exclusive content and updates

Pin It on Pinterest