• This is an assessment test.
  • To draw maximum benefit, study the concepts for the topic concerned.
  • Kindly take the tests in this series with a pre-defined schedule.

Arithmetic : Level 1 Test -10

Congratulations - you have completed Arithmetic : Level 1 Test -10. You scored %%SCORE%% out of %%TOTAL%%. You correct answer percentage: %%PERCENTAGE%% . Your performance has been rated as %%RATING%%
Your answers are highlighted below.
Question 1
A boatman goes 2 km against the current of the stream in 1 h and goes 1 km along the current in 10 min. How long will he take to travel 5 km in stationary water?
A
1 h 30 min
B
1 h 15 min
C
1 h
D
40 min
Question 1 Explanation: 
Speed of the boatman in upstream = 2 km/h
Speed of the boatman in downstream = 1/10 x 60 = 6 km/h
Therefore the speed in the stationary water = (2+6)/ 2 = 4 km/h
Therefore time will be = 5/4 = 1h and 15 min.
Question 2
A man rowed against a stream flowing 1.5 km/h to a certain point and then turned back, stopping 2 km short of the place from where he originally started. If the whole time occupied in rowing was 2 h 10 min and his uniform speed in still water is 4.5 km/h, the man went up the stream a distance of:
A
4 km
B
8 km
C
7 km
D
5 km
Question 2 Explanation: 
Speed of the man = 1.5km/h
Let d be the distance travelled by him in upstream
Therefore his return distance will be = (d – 2)
Speed of man in still water = 4.5 km/h
So therefore {d/ (4.5 – 1.5)} – {(d – 2)/(4.5 + 1.5)} = 2 h 10m
(2d  + d – 2)/6 = 21/6 d = 5 km
Question 3
A, Band C can do a work in 8, 16 and 24 days respectively. They all begin together. A continues to work till it is finished, C left after 2 days and B one day before its completion. In what time is the work finished?
A
7 days
B
5 days
C
6 days
D
Cannot be determined
Question 3 Explanation: 
Let us suppose the work will finish in D days
So , d/8 + (d-1)/16  + 2/24 = 1
d = 5 Hence, the work will be done in 5 days
Question 4
Two pipes can fill a tank in 10 h and 15 h respectively. However, leakage at the bottom of the tank delays the filling of the tank by 3 h when both the pipes are open simultaneously. How much time would the leak take to empty the full cistern?
A
22 h
B
18 h
C
12 h
D
21 h
Question 4 Explanation: 
Both the pipes will fill the tank in 1/10 +1/15 = 1/6 = 6 h
And due to the leakage the tank will fill in 6+3 hours i.e. 9 hours
Since we know that if pipe a fill the tank in x hours and pipe b empty the tank
in y hours then the time taken to fill the tank = 1/x -1/y
Therefore 1/6 – 1/9 = 1/18 = 18 hours
Question 5
Two pipes can fill a cistern in 15 min and 18 min respectively. Both the pipes are operating together, but 3 min before the cistern is full, the first pipe is closed. The cistern will be filled now in:
A
91/7
B
33/11 min
C
73/11min
D
None of these
Question 5 Explanation: 
Let d be the time which is taken by both the pipes to fill the tank
Given that the first tap is closed 3 minutes before Therefore (d – 3 ) /15 + d/18 = 1
d = 108/11
So d = 99/11 min
Once you are finished, click the button below. Any items you have not completed will be marked incorrect. Get Results
There are 5 questions to complete.
List
Return
Shaded items are complete.
12345
End
Return

Want to explore more Arithmetic Tests?

Explore Our Arithmetic Tests

Get Posts Like This Sent to your Email
Updates for Free Live sessions and offers are sent on mail. Don't worry: we do not send too many emails..:)
Get Posts Like This Sent to your Email
Updates for Free Live sessions and offers are sent on mail. Don't worry: we do not send too many emails..:)
Join Our Newsletter
Get the latest updates from our side, including offers and free live updates, on email.
Join Our Newsletter
Leverage agile frameworks to provide a robust synopsis for high level overviews.
Join our Free TELEGRAM GROUP for exclusive content and updates
Join our Free TELEGRAM GROUP for exclusive content and updates

Pin It on Pinterest