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## Arithmetic : Level 1 Test -7

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*Arithmetic : Level 1 Test -7*.You scored %%SCORE%% out of %%TOTAL%%.You correct answer percentage: %%PERCENTAGE%% .Your performance has been rated as %%RATING%% Your answers are highlighted below.

Question 1 |

Richa wanted to sell her two chairs that cost her a total of Rs. 545. She sold both the chairs. On selling one chair, she got 15% profit but she also generated a loss 12% on the other one. She did not get any profit and any loss in the whole transaction so .What is the cost price of the chair that she sold for a profit?

Rs. 239.56 | |

Rs. 237.65 | |

Rs. 245.23 | |

None |

Question 1 Explanation:

Let the cost price of chair with profit = P

So the cost price of the second chair will be = 545 – P

Because there is no profit no loss in the whole transaction

115P/100 + (545 – P)88/100 = 545

115 P + 47960 – 88 P = 54500

27P = 6540

By solving it for P

The cost price of chair = Rs. 242.222

Hence option D is the right answer

So the cost price of the second chair will be = 545 – P

Because there is no profit no loss in the whole transaction

115P/100 + (545 – P)88/100 = 545

115 P + 47960 – 88 P = 54500

27P = 6540

By solving it for P

The cost price of chair = Rs. 242.222

Hence option D is the right answer

Question 2 |

Meera invested some money in Local Community and obtained a profit of 6%. She again invested her money but this time she generated a loss of 9% on this transaction. If the investment of money was in the ratio of 2:3, then what is the loss percentage in the whole transaction?

3% | |

4% | |

5% | |

6% |

Question 2 Explanation:

Let the money is invested is 2Y and 3Y

So the total money invested = 5Y

Now money obtained A

A=(2Y x 106/100) + ( 3Y x 91/100)

A= 97Y/20

Now the loss will be

Loss=5Y – 97Y/20

Loss=3Y/20

So the loss percentage will be

[{(3Y/20) / 5Y} x 100]%

Loss % = 3%

So option A is the right answer

So the total money invested = 5Y

Now money obtained A

A=(2Y x 106/100) + ( 3Y x 91/100)

A= 97Y/20

Now the loss will be

Loss=5Y – 97Y/20

Loss=3Y/20

So the loss percentage will be

[{(3Y/20) / 5Y} x 100]%

Loss % = 3%

So option A is the right answer

Question 3 |

Meera invested some money in three different schemes for 2 years, 4 years, and 6 years at different rate of interests i.e. 5% , 10%, 15%. At the completion of the each scheme Meera get equal money. Then what could be the ratio of investment for 2, 4, 6 years respectively?

9: 4: 36 | |

4: 9: 36 | |

3:4: 36 | |

36: 9: 4 |

Question 3 Explanation:

Let P: Q: R be the ratio of investment

Simple interest on P = Simple interest on Q = Simple interest of R

So P x 2 x 5/100 = Q x 4 x 10/100 = R x 6 x 15/100

P/10= 2Q/5 = 9R/10

So the ratio will be

P:Q:R = 36:9:4

Simple interest on P = Simple interest on Q = Simple interest of R

So P x 2 x 5/100 = Q x 4 x 10/100 = R x 6 x 15/100

P/10= 2Q/5 = 9R/10

So the ratio will be

P:Q:R = 36:9:4

Question 4 |

Natasha sold her laptop by giving 12 % discount and she still gains a profit of 15%. So how much percentage above the cost price does she marked on her laptop.

28.56% | |

30.68% | |

22.22% | |

None of these |

Question 4 Explanation:

Let the cost price of the laptop be Rs. 10000

If Natasha gained 15% profit then the selling price is Rs. 11500

Discount = 12% on marked price

Let the marked price is P

Then P x 88/100 = 11500

P = Rs. 13068.18

This is 30.68% more on cost price

If Natasha gained 15% profit then the selling price is Rs. 11500

Discount = 12% on marked price

Let the marked price is P

Then P x 88/100 = 11500

P = Rs. 13068.18

This is 30.68% more on cost price

Question 5 |

Meera went to a Laptop shop. The cash price of laptop was Rs. 24945. She paid Rs. 3945 and gave the rest of money in two equal annual instalments. If the rate of interest is 5% compounded annually then what was the value of each installment?

Rs. 11293.90 | |

Rs. 11298.90 | |

Rs. 11500 | |

Rs. 10500 |

Question 5 Explanation:

Cash price of the laptop = Rs. 24945

Amount paid by Meera = Rs. 3945

Amount left = Rs. 21000

Now let the value of instalment is P

So the amount paid is

{P/(1+R/100)

Where P is the value of first installment

And R = 5%

By solving this

{P/(1+5/100)

P = (21000 x 441)/820

P = 11293.90

Amount paid by Meera = Rs. 3945

Amount left = Rs. 21000

Now let the value of instalment is P

So the amount paid is

{P/(1+R/100)

^{2}} + {P/(1+R/100)^{1}} = 21000Where P is the value of first installment

And R = 5%

By solving this

{P/(1+5/100)

^{2}} + {P/(1+R/100)^{1}}= 21000P = (21000 x 441)/820

P = 11293.90

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