- This is an assessment test.
- To draw maximum benefit, study the concepts for the topic concerned.
- Kindly take the tests in this series with a pre-defined schedule.
Arithmetic : Level 2 Test -7
Please wait while the activity loads. If this activity does not load, try refreshing your browser. Also, this page requires javascript. Please visit using a browser with javascript enabled.
Congratulations - you have completed Arithmetic : Level 2 Test -7.You scored %%SCORE%% out of %%TOTAL%%.You correct answer percentage: %%PERCENTAGE%% .Your performance has been rated as %%RATING%%
Your answers are highlighted below.
Question 1 |
A train travels a distance of 600 km at a constant speed. If the speed of the train is increased by 5 km/h, the journey would take 4 h less. Find the speed of the train.
100 km/h | |
25 km/h | |
50 km/h | |
None of these |
Question 1 Explanation:
Distance = 600 km/h
Let the speed of the train = s km/h
Now increased speed = (s + 5) km/h
So 600/s = 600/(s+5) + 4
600/s - 600/(s+5) = 4
600[5/s(s+5)]= 4
s = 25 km/h
Let the speed of the train = s km/h
Now increased speed = (s + 5) km/h
So 600/s = 600/(s+5) + 4
600/s - 600/(s+5) = 4
600[5/s(s+5)]= 4
s = 25 km/h
Question 2 |
Three pipes A, B and C can fill a tank in 20 min, 10 min and 30 min respectively. When the tank is empty, all the three pipes are opened. A, Band C discharge chemical solutions x, y and z respectively. The proportion of solution y in the liquid in the tank after 3 min is
6/11 | |
7/11 | |
8/11 | |
5/11 |
Question 2 Explanation:
Work done by the pipes in one minutes = 1/20 + 1/10 +1/30
So the work done by the pipes in 3 minutes = 3/20 + 3/10 +3/30 = 11/20
The work done by the 2nd pipe in one minute = 1/10
The work done by the 2nd pipe in three minutes = 3/10
So the required ratio will be = (3/10) / (11/20) = 6/11
So the work done by the pipes in 3 minutes = 3/20 + 3/10 +3/30 = 11/20
The work done by the 2nd pipe in one minute = 1/10
The work done by the 2nd pipe in three minutes = 3/10
So the required ratio will be = (3/10) / (11/20) = 6/11
Question 3 |
Three taps A, Band C can fill a tank in 12, 15 and 20 h respectively. If A is open all the time and B and C is open for one hour each alternatively; the tank will be filled in
6 h | |
7 h | |
5 h | |
None of these |
Question 3 Explanation:
Tap A and B can fill the tank in =1/12 + 1/15 = 3/20
Tap A and C can fill the tank in =1/12 + 1/20 = 2/15
Work done by all the taps in 2 hours = 3/20 + 2/15 = 17/60
Filling done in 6 hours = 17/60 x 3 = 51/60
So remaining work is = 1 – 51/60 = 3/20
Now the taps which are opened are A and B and the work done by the taps in one hour is 3/20 as discussed earlier,
so the total time for the whole filling would be = 7 hours
Tap A and C can fill the tank in =1/12 + 1/20 = 2/15
Work done by all the taps in 2 hours = 3/20 + 2/15 = 17/60
Filling done in 6 hours = 17/60 x 3 = 51/60
So remaining work is = 1 – 51/60 = 3/20
Now the taps which are opened are A and B and the work done by the taps in one hour is 3/20 as discussed earlier,
so the total time for the whole filling would be = 7 hours
Question 4 |
A plane left 30 min later than its scheduled time to reach its destination 1500 km away. In order to reach in time it increases its speed by 250 km/h. What is its original speed?
1000 km/h | |
750 km/h | |
600 km/h | |
800 km/h |
Question 4 Explanation:
Let the actual speed of the plane = S km/h
Let the actual time taken = T h
Distance = 1500 km
Therefore T = 1500/S…………………………………a
Now acc. to question
1500/(S + 250) = T – 30/60 ………………………..b
1500/ (s+ 250) = 1500/s – 30/60
Solving the above equation S = 750 km/h
Let the actual time taken = T h
Distance = 1500 km
Therefore T = 1500/S…………………………………a
Now acc. to question
1500/(S + 250) = T – 30/60 ………………………..b
1500/ (s+ 250) = 1500/s – 30/60
Solving the above equation S = 750 km/h
Question 5 |
A computer can perform 30 identical tasks in 6 h. At that rate, what is the approximately minimum number of computers that should be assigned to complete 80 of the tasks within 3 h?
12 | |
6.66 | |
5.33 | |
16 |
Question 5 Explanation:
6 hour = 30 tasks
1 hour = 5 tasks
3 hour = 15 tasks
So 15 article are done by 1 computer in 3 hours
15N = 80
N = 80 / 15 = approx. 5.33 times
1 hour = 5 tasks
3 hour = 15 tasks
So 15 article are done by 1 computer in 3 hours
15N = 80
N = 80 / 15 = approx. 5.33 times
Once you are finished, click the button below. Any items you have not completed will be marked incorrect.
There are 5 questions to complete.
List |
You have completed
questions
question
Your score is
Correct
Wrong
Partial-Credit
You have not finished your quiz. If you leave this page, your progress will be lost.
Correct Answer
You Selected
Not Attempted
Final Score on Quiz
Attempted Questions Correct
Attempted Questions Wrong
Questions Not Attempted
Total Questions on Quiz
Question Details
Results
Date
Score
Hint
Time allowed
minutes
seconds
Time used
Answer Choice(s) Selected
Question Text
All done
Need more practice!
Keep trying!
Not bad!
Good work!
Perfect!