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Arithmetic: Percentage Test -2

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Question 1
In an examination, 40% marks are required to pass. A obtains 10% less than the number of marks required to pass. B obtains 111/9 % less than A and C obtained   413/17% less than the number of marks obtained by A and B together. What marks did C get?
A
50
B
40
C
35
D
45
Question 1 Explanation: 
Let the total marks be 100
Minimum marks required to pass the exam =40
Marks obtained by A = 40 – (40 x 10/100) = 36 marks
Marks obtained by B= 36 – (100/9 x 36/100) = 32 marks
Marks obtained by C ==(36 +32) x 700/(17 x100)=40 marks
Question 2
An article is listed at Rs 65. A customer bought this article for Rs 56.16 with two successive discounts, out of which one is 10%. The other discount of this discount scheme that was allowed by the shopkeeper is:
A
4%
B
3%
C
6%
D
2.5%
Question 2 Explanation: 
let the discount be D
Therefore 65 x (90)/100 x (100 –D)/100 = 56.16
100 – D = (56.16 x 100 x100) / (65 x 9)
100 – D = 96
D = 4%
Question 3
Mohan spends 40% of his salary on food items, 50% of the remaining on transport, 30% of the remaining on clothes , after spending on food and transport; and saves the balance. If he saves Rs 630 every month, what is his monthly salary?
A
Rs 1500
B
Rs 3000
C
Rs 5000
D
Rs 6500
Question 3 Explanation: 
4s/10 + (10s-4s)/10 x 50/100 +(6s-3s)/10 x 30/100 + saving = s
4s/10 + 6s/10 x 50/100 +3s/10 x 30/100 + saving = s
=> 4s/10 + 3s/10 + 9s/100 + 630 =s
=> 630 = (100s - 70s – 9s)/100
=> 630 = 21s/100
=> s = Rs 3000
Question 4
The wheat sold by a grocer contained 10% low quality wheat. What quantity of good quantity wheat should be added to 150 kg of wheat so that the percentage of low quality wheat becomes 5%?
A
85 kg
B
50 kg
C
135 kg
D
150 kg
Question 4 Explanation: 
First, let’s calculate the low quality wheat: 10% of 150 = 15
This 15kg should now be 5% of the total amount of wheat.
Therefore the total amount of wheat becomes 300 kg
Originally, the wheat which is of good quality was 150 -15 =135kg
To become 5% low quality of wheat, we add the 150kg of good quality wheat.
Question 5
The present population of a village is 5500. If the number of males increases by 11 % and the number of females increases by 20%, then the population will become 6330. What is the present population of females in the village?
A
3000
B
3500
C
2500
D
2000
Question 5 Explanation: 
Let the present population of male = m
Let the present population of female = f
So m + f= 5500................................................1
111/100m +120/100f =6330
111m +120f =633000....................................2
On solving 1 and 2
f = 2500
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