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## Arithmetic: Percentage Test -5

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Question 1 |

A person bought two tables for Rs. 2200. He sells one at 5% loss and the other at 6% profit and thus on the whole he neither gains nor loses. Find the cost price of each table.

Rs 1500, Rs 700 | |

Rs 2000, Rs 200 | |

Rs 1200, Rs 1000 | |

Rs 1100, Rs 1100 |

Question 1 Explanation:

Let the cost of table = t

Then the cost price of other will be = (2200 –t)

=> t x (95/100) + (2200 – t) x 106/100 =2200

=> 95t + 233200 – 106 t =220000

=> 11t = 13200

=> t = 1200 Rs and 2200 – t =1000 Rs

Then the cost price of other will be = (2200 –t)

=> t x (95/100) + (2200 – t) x 106/100 =2200

=> 95t + 233200 – 106 t =220000

=> 11t = 13200

=> t = 1200 Rs and 2200 – t =1000 Rs

Question 2 |

A tree was planted three years ago. The rate of its growth is 30% per annum. If at present, the height of the tree is 670 cm, what was it when the tree was planted?

305 cm | |

500 cm | |

405 cm | |

625 cm |

Question 2 Explanation:

Let the height of the tree be (h)

=> h x {1+(30/100)

=> h = 670 x {( 10 x 10 x10 )/(13 x 13 x 13)} = 305 approx.

=> h x {1+(30/100)

^{3}} =670=> h = 670 x {( 10 x 10 x10 )/(13 x 13 x 13)} = 305 approx.

Question 3 |

When the price of sugar was increased by 32%, a family reduced its consumption in such a way that the expenditure on sugar was only 10% more than before. If 30 kg per month were consumed before, find the new monthly consumption.

42 kg | |

35 kg | |

25 kg | |

16 kg |

Question 3 Explanation:

Let the price of the sugar be Rs(p) / kg

=> Initial expenditure = 30p

=> new expenditure = 33p

=> new monthly consumption = 33p/1.32p = 25kg

=> Initial expenditure = 30p

=> new expenditure = 33p

=> new monthly consumption = 33p/1.32p = 25kg

Question 4 |

A man's income is increased by Rs. 1200 and at the same time, the rate of tax to be paid is reduced from 12% to 10%. He now pays the same amount of tax as before. What is his increased income, if 20% of his income is exempted from tax in both cases?

Rs 6300 | |

Rs 7200 | |

Rs 4500 | |

Rs 6500 |

Question 4 Explanation:

Let the increased income be P

=> (P – 1200) x 80/100 x 12/100 = P x 80/100 x10/100

=> 12P – 14400 =10p

=> P = Rs. 7200

=> (P – 1200) x 80/100 x 12/100 = P x 80/100 x10/100

=> 12P – 14400 =10p

=> P = Rs. 7200

Question 5 |

Mr. Bharat Toni buys a generator for Rs. 100000 and rents it. He puts 12.5% of each month's rent aside for upkeep and repairs, pays Rs. 325 per year as taxes and realizes 5.5% annually on his investment. Find the monthly rent.

Rs 634.76 | |

Rs 654.76 | |

Rs 554.76 | |

Rs 456.32 |

Question 5 Explanation:

Let Monthly rent be = (r)

=> 12r – 12r x (12.5/100) -325 = 100000 x (5.5/100)

=> 12r – 1.5r – 325 = 5500

=> r = (5500 +325)/ 10.5 = Rs 554.76

=> 12r – 12r x (12.5/100) -325 = 100000 x (5.5/100)

=> 12r – 1.5r – 325 = 5500

=> r = (5500 +325)/ 10.5 = Rs 554.76

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