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## Arithmetic: Percentage Test -6

Congratulations - you have completed

*Arithmetic: Percentage Test -6*. You scored %%SCORE%% out of %%TOTAL%%. You correct answer percentage: %%PERCENTAGE%% . Your performance has been rated as %%RATING%% Your answers are highlighted below.

Question 1 |

A solution of sugar syrup has 15% sugar solution has 5% sugar. How many litres of t solution must be added to 20 L of the first make a solution of 10% sugar?

10 L | |

5 L | |

15 L | |

20 L |

Question 1 Explanation:

Let the solution which is to be added in the second solution is (s)

=> [{(15 x 20) + (5 x s)} / 20 + s] = 10

=> 300 + 5s = 200 +10s

=> s = 100/5 = 20L

=> [{(15 x 20) + (5 x s)} / 20 + s] = 10

=> 300 + 5s = 200 +10s

=> s = 100/5 = 20L

Question 2 |

An 8 L cylinder contains a mixture of oxygen and nitrogen, the volume of oxygen being 16% of total volume. A few litres of the mixture is released and an equal amount of nitrogen is added. Then, the same amount of the mixture as before is released and replaced by nitrogen for the second time. As result, the oxygen content becomes 9% of total volume. How many litres of mixture is released each time?

7 L | |

4 L | |

2 L | |

None of these |

Question 2 Explanation:

We solve this question with the help of answer options.

Total mixture = 8L

Oxygen is 1.28

Nitrogen = 6.72

If we release 2L in each time then we have

1.28 – (2 x 16/100) =0.96L

Oxygen now becomes 12% of the mixture.

After the 2

0.96 – (2x12/100) = 0.72L which is the 9% of 8

Hence the option c is the right answer

Total mixture = 8L

Oxygen is 1.28

Nitrogen = 6.72

If we release 2L in each time then we have

1.28 – (2 x 16/100) =0.96L

Oxygen now becomes 12% of the mixture.

After the 2

^{nd}release0.96 – (2x12/100) = 0.72L which is the 9% of 8

Hence the option c is the right answer

Question 3 |

Two gallons of a mixture of spirit and water contain 12% of water. They are added to 3 gallons of another mixture, containing 7% of water and half a gallon of water is then added to the whole. Find the percentage of water in the resulting mixture.

17 ^{3}/_{11}% | |

16 ^{3}/_{11} % | |

14 ^{3}/_{11} % | |

None of these |

Question 3 Explanation:

Mixture = 2 +3+0.5= 5.5 gallon

Water = 2 x 12/100 + 3 x 7/100 + 0.5

= 0.95 gallon

Therefore required percentage = 0.95/5.5 x 100

= 190 /11 = 17

Water = 2 x 12/100 + 3 x 7/100 + 0.5

= 0.95 gallon

Therefore required percentage = 0.95/5.5 x 100

= 190 /11 = 17

^{3}/_{11}%Question 4 |

If a bucket is 80% full, then it contains 2 L more water than when it is 66

^{2}/_{3}% full. What is the capacity of the bucket?10 L | |

15 L | |

16 ^{2}/_{3} L | |

20 L |

Question 4 Explanation:

Let the capacity of the bucket is (c)

Therefore 0.80c = 0.667c + 2

=> c = 2/0.133 =15L

Therefore 0.80c = 0.667c + 2

=> c = 2/0.133 =15L

Question 5 |

The difference between 38% of a number and 24% of the same number is 135.10. What is 40% of that number?

394 | |

370 | |

378 | |

386 |

Question 5 Explanation:

Let the number be (n)

Then 0.38n – 0.24n = 135.10

=> n= (135.10/0.14) = 965

=> 0.4n = 0.4 x 965 =386

Then 0.38n – 0.24n = 135.10

=> n= (135.10/0.14) = 965

=> 0.4n = 0.4 x 965 =386

Once you are finished, click the button below. Any items you have not completed will be marked incorrect.

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### Table of Contents

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### How to study this lesson?

It is actually simple to study this lesson.

Go through the given concepts and their corresponding exercises.

Then, solve the percentage practice tests and perfect the skills you have learnt