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Arithmetic: Ratio and Proportion Test-1

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Question 1
Two numbers are in the ratio of 5:4, and their sum is 261 then what will be the smaller number?
A
145
B
116
C
45
D
16
Question 1 Explanation: 
Since the numbers are 5:4
And their sum is 261
Hence the numbers are = 5/9 x 261 =145
And the second number is 4/9 x 261 = 116
So the smallest number =116 i.e. option B
Question 2
Richa, Meera, Manpreet went to coffee shop and all had a cup of black coffee each, the ratio of the bill shared by them was (Richa : Meera : Manpreet = 3 : 4 : 5). If the bill was of Rs. 348 then find how much money was paid by Richa?
A
90
B
87
C
76
D
43
Question 2 Explanation: 
The ratio of the bill shared by them R : Mr : Mt = 3 : 4 : 5
The amount of the bill = Rs. 348
Therefore Richa paid = 3/12 x 348 = Rs. 87
Question 3
If the Incomes of Richa and Manpreet are in the ratio of 3:4 and the incomes of Manpreet and Ankita are 7:9 then what will be the ratio of incomes of Richa, Manpreet and Ankita ?
A
21:34:45
B
21:32:54
C
21:28:36
D
21:30:36
Question 3 Explanation: 
Richa and Manpreet = 3:4
Manpreet and Ankita = 7:9
So Richa : Manpreet : Ankita
7 x 3 : 7 x 4 : 9 x 4 = 21 : 28 : 36
Question 4
The first, second and third class fares between two stations were 10 : 8 : 3 and the number of first,  second and third class passengers between the two  stations in a day was 3 : 4 : 10. The sale of tickets to passengers running between two stations on that day was Rs.  8050. How much was realized by the sale of second class tickets?
A
Rs. 3000
B
Rs. 2800
C
Rs. 4500
D
Rs. 3500
Question 4 Explanation: 
The first, second and third class fares between two stations were 10 : 8 : 3
Therefore second class ticket ={(8 x4)/ 30+ 32+ 30}  x 8050
= 32/92 x 8050 =Rs. 2800
Question 5
A person distributes his pens among four friends A, B, C and D in the ratio 1/3 : 1/4 : 1/5 : 1/6. What isthe minimum number of pens that the person should  have?
A
65
B
55
C
23
D
57
Question 5 Explanation: 
LCM of 3,4,5,6 is 60
Therefore
1/3 x 60 = 20
1/4 x 60 = 15
1/5 x 60 = 12
1/6 x 60 = 10
A, B, C and D in the ratio 1/3 : 1/4 : 1/5 : 1/6 = 20 : 15: 12: 10  So, the minimum number of pens that the person  should have
= 20 + 15 + 12 + 10 = 57
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