- This is an assessment test.
- These tests focus on the basics of Maths and are meant to indicate your preparation level for the subject.
- Kindly take the tests in this series with a pre-defined schedule.

## Basic Maths: Test 15

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Question 1 |

$ \displaystyle If\,\frac{50}{p}=\frac{p}{12\frac{1}{2}}$ then the value of p is:

$ \displaystyle \frac{25}{2}$ | |

$ \displaystyle \frac{4}{25}$ | |

$ \displaystyle 4$ | |

$ \displaystyle 25$ |

Question 1 Explanation:

$ \displaystyle \begin{array}{l}\,\frac{50}{p}=\frac{p}{12\frac{1}{2}}\\\Rightarrow \frac{50}{p}=\frac{2p}{25}\\\Rightarrow 2{{p}^{2}}=50\times 25\\\Rightarrow 2{{p}^{2}}=1250\\Therefore\,\,p=25\end{array}$

Question 2 |

$ \displaystyle \frac{{{\left( 6.25 \right)}^{\frac{1}{2}}}\times {{\left( 0.0144 \right)}^{\frac{1}{2}}}+3}{{{\left( 0.027 \right)}^{\frac{1}{3}}}\times {{\left( 81 \right)}^{\frac{1}{4}}}}$

0.14
| |

1.46 | |

1.36 | |

3.6 |

Question 2 Explanation:

$ \displaystyle \begin{array}{l}\frac{{{\left( 6.25 \right)}^{\frac{1}{2}}}\times {{\left( 0.0144 \right)}^{\frac{1}{2}}}+3}{{{\left( 0.027 \right)}^{\frac{1}{3}}}\times {{\left( 81 \right)}^{\frac{1}{4}}}}\\=\frac{2.5\times 0.12+3}{0.3\times 3}=\frac{0.3+3}{0.9}=\frac{3.3}{0.9}=3.6\end{array}$

Question 3 |

The value of $ \displaystyle \frac{8}{9}\times \frac{3}{\frac{5}{6}\div \frac{2}{3}\,\,of\,1\frac{1}{4}}$

$ \displaystyle \frac{8}{3}$ | |

$ \displaystyle 1$ | |

$ \displaystyle \frac{1}{2}$ | |

$ \displaystyle \frac{2}{3}$ |

Question 3 Explanation:

$ \displaystyle \begin{array}{l}\frac{8}{9}\times \frac{3}{\frac{5}{6}\div \frac{2}{3}\,\,of\,1\frac{1}{4}}\\=\frac{8}{9}\times \frac{3}{\frac{5}{6}\div \frac{2}{3}\,\,of\,\frac{5}{4}}\\=\frac{8}{9}\times \frac{3}{\frac{5}{6}\div \frac{10}{12}\,\,}\\=\frac{8}{9}\times \frac{3}{\frac{5}{6}\times \frac{12}{10}\,\,}=\frac{8}{9}\times \frac{3}{1}=8/3\end{array}$

Question 4 |

$ \displaystyle 4-\left[ 5-\left\{ 2+\left( -5+6-2 \right)2 \right\} \right]$ is equal to

-1
| |

2 | |

0 | |

-2 |

Question 4 Explanation:

$ \displaystyle \begin{array}{l}p=4-\left[ 5-\left\{ 2+\left( -1 \right)2 \right\} \right]\\=4\times \left[ 5-\left\{ 2-2 \right\} \right]\\=4-\left[ 5-0 \right]\\=4-5=-1\end{array}$

Question 5 |

On simplification, 50−(1002/20.04) is equal to:

329
| |

0 | |

2993 | |

2543 |

Question 5 Explanation:

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ans 2 varies by a factor of 10