Basic Maths: Test 15

This is an assessment test.
These tests focus on the basics of Maths and are meant to indicate your preparation level for the subject.
Kindly take the tests in this series with a pre-defined schedule.

Basic Maths: Test 15

Please wait while the activity loads.
If this activity does not load, try refreshing your browser. Also, this page requires javascript. Please visit using a browser with javascript enabled.

If loading fails, click here to try again

Congratulations - you have completed Basic Maths: Test 15.You scored %%SCORE%% out of %%TOTAL%%.You correct answer percentage: %%PERCENTAGE%% .Your performance has been rated as %%RATING%%

Your answers are highlighted below.

Question 1

$ \displaystyle If\,\frac{50}{p}=\frac{p}{12\frac{1}{2}}$ then the value of p is:

A	$ \displaystyle \frac{25}{2}$
B	$ \displaystyle \frac{4}{25}$
C	$ \displaystyle 4$
D	$ \displaystyle 25$

Question 1 Explanation:

$ \displaystyle \begin{array}{l}\,\frac{50}{p}=\frac{p}{12\frac{1}{2}}\\\Rightarrow \frac{50}{p}=\frac{2p}{25}\\\Rightarrow 2{{p}^{2}}=50\times 25\\\Rightarrow 2{{p}^{2}}=1250\\Therefore\,\,p=25\end{array}$

Question 2

$ \displaystyle \frac{{{\left( 6.25 \right)}^{\frac{1}{2}}}\times {{\left( 0.0144 \right)}^{\frac{1}{2}}}+3}{{{\left( 0.027 \right)}^{\frac{1}{3}}}\times {{\left( 81 \right)}^{\frac{1}{4}}}}$

A	0.14
B	1.46
C	1.36
D	3.6

Question 2 Explanation:

$ \displaystyle \begin{array}{l}\frac{{{\left( 6.25 \right)}^{\frac{1}{2}}}\times {{\left( 0.0144 \right)}^{\frac{1}{2}}}+3}{{{\left( 0.027 \right)}^{\frac{1}{3}}}\times {{\left( 81 \right)}^{\frac{1}{4}}}}\\=\frac{2.5\times 0.12+3}{0.3\times 3}=\frac{0.3+3}{0.9}=\frac{3.3}{0.9}=3.6\end{array}$

Question 3

The value of $ \displaystyle \frac{8}{9}\times \frac{3}{\frac{5}{6}\div \frac{2}{3}\,\,of\,1\frac{1}{4}}$

A	$ \displaystyle \frac{8}{3}$
B	$ \displaystyle 1$
C	$ \displaystyle \frac{1}{2}$
D	$ \displaystyle \frac{2}{3}$

Question 3 Explanation:

$ \displaystyle \begin{array}{l}\frac{8}{9}\times \frac{3}{\frac{5}{6}\div \frac{2}{3}\,\,of\,1\frac{1}{4}}\\=\frac{8}{9}\times \frac{3}{\frac{5}{6}\div \frac{2}{3}\,\,of\,\frac{5}{4}}\\=\frac{8}{9}\times \frac{3}{\frac{5}{6}\div \frac{10}{12}\,\,}\\=\frac{8}{9}\times \frac{3}{\frac{5}{6}\times \frac{12}{10}\,\,}=\frac{8}{9}\times \frac{3}{1}=8/3\end{array}$

Question 4

$ \displaystyle 4-\left[ 5-\left\{ 2+\left( -5+6-2 \right)2 \right\} \right]$ is equal to

A	-1
B	2
C	0
D	-2

Question 4 Explanation:

$ \displaystyle \begin{array}{l}p=4-\left[ 5-\left\{ 2+\left( -1 \right)2 \right\} \right]\\=4\times \left[ 5-\left\{ 2-2 \right\} \right]\\=4-\left[ 5-0 \right]\\=4-5=-1\end{array}$

Question 5

On simplification, 50−(1002/20.04) is equal to: