 This is an assessment test.
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Basic Maths: Test 19
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Question 1 
$ \displaystyle \left( 0.\overline{11}+0.\overline{22} \right)\times 2$
$ \displaystyle 1.\overline{9}$  
3  
2/3  
$ \displaystyle 0.\overline{3}$ 
Question 1 Explanation:
Expression
$ \displaystyle \begin{array}{l}=\left( 0.\overline{11}+0.\overline{22} \right)\times 2\\=\left( \frac{11}{99}+\frac{22}{99} \right)\times 2\\=\frac{33}{99}\times 2\\=2/3\end{array}$
Question 2 
$ \displaystyle \sqrt{0.014\times 0.14a}=0.014\times 0.14\sqrt{b},\,\,find\,\,\,the\,\,\,value\,\,\,of\,\,\,\frac{a}{b}.$
0.000196
 
0.00196  
0.0196  
0.196 
Question 2 Explanation:
$\displaystyle \begin{array}{l}=\sqrt{0.014\times 0.14a}=0.014\times 0.14\sqrt{b}\\On\,\,squaring\,\,\,both\,\,sides,\\0.014\times 0.14a={{\left( 0.014 \right)}^{2}}\times {{\left( 0.14 \right)}^{2}}b\\therefore\,\,\,\frac{a}{b}=0.014\times 0.14=0.00196\end{array}$
Question 3 
$ \displaystyle \left\{ \frac{{{\left( 0.1 \right)}^{2}}{{\left( 0.01 \right)}^{2}}}{0.0001}+2 \right\}$
is equal to
is equal to
1010  
110  
101  
100

Question 3 Explanation:
$ \displaystyle \begin{array}{l}=\frac{0.010.0001}{0.0001}+2=\frac{0.0099}{0.0001}+2\\=99+2=101\end{array}$
Question 4 
$ \displaystyle \sqrt{1\frac{1}{4}\times \frac{64}{125}\times 3.24}$
is equal to
is equal to
$ \displaystyle 1\frac{1}{25}$  
$ \displaystyle \frac{36}{25}$  
$ \displaystyle \frac{23}{25}$  
$ \displaystyle \frac{21}{25}$ 
Question 4 Explanation:
$ \displaystyle \begin{array}{l}=\sqrt{\frac{5}{4}\times \frac{64}{125}\times 3.24}\\=\sqrt{\frac{16}{25}\times \frac{324}{100}}\\=\frac{4}{5}\times \frac{18}{10}\\=\frac{36}{25}\end{array}$
Question 5 
$ \displaystyle \frac{\left( 5+5+5+5 \right)\div 4}{3+3+3+3\div 2}$
1  
$ \displaystyle \frac{3}{10}$  
$ \displaystyle \frac{4}{9}$  
$ \displaystyle \frac{10}{21}$ 
Question 5 Explanation:
$ \displaystyle =\frac{20\div 4}{9+3\div 2}=\frac{10}{21}$
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