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• This is an assessment test.
• These tests focus on the basics of Maths and are meant to indicate your preparation level for the subject.
• Kindly take the tests in this series with a pre-defined schedule.

Basic Maths: Test 19

Congratulations - you have completed Basic Maths: Test 19. You scored %%SCORE%% out of %%TOTAL%%. You correct answer percentage: %%PERCENTAGE%% . Your performance has been rated as %%RATING%%
 Question 1
$\displaystyle \left( 0.\overline{11}+0.\overline{22} \right)\times 2$
 A $\displaystyle 1.\overline{9}$ B 3 C 2/3 D $\displaystyle 0.\overline{3}$
Question 1 Explanation:
Expression $\displaystyle \begin{array}{l}=\left( 0.\overline{11}+0.\overline{22} \right)\times 2\\=\left( \frac{11}{99}+\frac{22}{99} \right)\times 2\\=\frac{33}{99}\times 2\\=2/3\end{array}$
 Question 2
$\displaystyle \sqrt{0.014\times 0.14a}=0.014\times 0.14\sqrt{b},\,\,find\,\,\,the\,\,\,value\,\,\,of\,\,\,\frac{a}{b}.$
 A 0.000196 B 0.00196 C 0.0196 D 0.196
Question 2 Explanation:
$\displaystyle \begin{array}{l}=\sqrt{0.014\times 0.14a}=0.014\times 0.14\sqrt{b}\\On\,\,squaring\,\,\,both\,\,sides,\\0.014\times 0.14a={{\left( 0.014 \right)}^{2}}\times {{\left( 0.14 \right)}^{2}}b\\therefore\,\,\,\frac{a}{b}=0.014\times 0.14=0.00196\end{array}$
 Question 3
$\displaystyle \left\{ \frac{{{\left( 0.1 \right)}^{2}}-{{\left( 0.01 \right)}^{2}}}{0.0001}+2 \right\}$
is equal to
 A 1010 B 110 C 101 D 100
Question 3 Explanation:
$\displaystyle \begin{array}{l}=\frac{0.01-0.0001}{0.0001}+2=\frac{0.0099}{0.0001}+2\\=99+2=101\end{array}$
 Question 4
$\displaystyle \sqrt{1\frac{1}{4}\times \frac{64}{125}\times 3.24}$
is equal to
 A $\displaystyle 1\frac{1}{25}$ B $\displaystyle \frac{36}{25}$ C $\displaystyle \frac{23}{25}$ D $\displaystyle \frac{21}{25}$
Question 4 Explanation:
$\displaystyle \begin{array}{l}=\sqrt{\frac{5}{4}\times \frac{64}{125}\times 3.24}\\=\sqrt{\frac{16}{25}\times \frac{324}{100}}\\=\frac{4}{5}\times \frac{18}{10}\\=\frac{36}{25}\end{array}$
 Question 5
$\displaystyle \frac{\left( 5+5+5+5 \right)\div 4}{3+3+3+3\div 2}$
 A 1 B $\displaystyle \frac{3}{10}$ C $\displaystyle \frac{4}{9}$ D $\displaystyle \frac{10}{21}$
Question 5 Explanation:
$\displaystyle =\frac{20\div 4}{9+3\div 2}=\frac{10}{21}$
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