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• This is an assessment test.
• These tests focus on the basics of Maths and are meant to indicate your preparation level for the subject.
• Kindly take the tests in this series with a pre-defined schedule.

## Basic Maths: Test 20

Congratulations - you have completed Basic Maths: Test 20. You scored %%SCORE%% out of %%TOTAL%%. You correct answer percentage: %%PERCENTAGE%% . Your performance has been rated as %%RATING%%
 Question 1
$\displaystyle \frac{{{\left( 0.05 \right)}^{2}}+{{\left( 0.41 \right)}^{2}}+{{\left( 0.073 \right)}^{2}}}{{{\left( 0.005 \right)}^{2}}+{{\left( 0.041 \right)}^{2}}+{{\left( 0.0073 \right)}^{2}}}$
 A 10 B 100 C 1000 D None of these
Question 1 Explanation:
$\displaystyle \begin{array}{l}Let\,\,0.05=x\,Therefore\,\,0.005=\frac{x}{10}\\0.41=c\,\,Therefore\,\,0.041=\frac{c}{10}\\and\,\,\,\,0.073\,\,=v\,\,therefore\,\,\,\,\,0.0073=\frac{v}{10}\\Therefore\,\,\exp ression\\=\frac{{{x}^{2}}+{{c}^{2}}+{{v}^{2}}}{{{\left( \frac{x}{10} \right)}^{2}}+{{\left( \frac{c}{10} \right)}^{2}}+{{\left( \frac{v}{10} \right)}^{2}}}\\=\frac{{{x}^{2}}+{{c}^{2}}+{{v}^{2}}}{\frac{1}{100}\left( {{x}^{2}}+{{c}^{2}}+{{v}^{2}} \right)}=100\end{array}$
 Question 2
$\displaystyle \frac{\left( 3\frac{1}{3}-2\frac{1}{2} \right)\div \frac{1}{2}\,\,of\,\,1\frac{1}{4}}{\frac{1}{3}+\frac{1}{5}\,\,of\,\,\frac{1}{9}}$
 A 1 B 15/4 C 1/5 D 1/2
Question 2 Explanation:
$\displaystyle \begin{array}{l}\,\frac{\left( \frac{10}{3}-\frac{5}{2} \right)\div \frac{5}{4}\,\times \frac{1}{2}}{\frac{1}{3}+\frac{1}{9}\,\times \frac{1}{5}}\\\frac{\left( \frac{20-15}{6} \right)\div \frac{5}{8}}{\frac{1}{3}+\frac{1}{45}}\\\frac{\frac{5}{6}\times \frac{8}{5}}{\frac{15+1}{45}}=\frac{45}{16}\times \frac{4}{3}=15/4\end{array}$
 Question 3
$\displaystyle \frac{9}{2}-\left[ 2\frac{1}{4}\div \left\{ 1\frac{1}{4}-\frac{1}{2}\left( 1\frac{1}{2}-\frac{1}{3}-\frac{1}{6} \right) \right\} \right]$ is
 A $1\frac{1}{2}$ B $\displaystyle 2\frac{1}{2}$ C $\displaystyle 3\frac{1}{2}$ D $\displaystyle 9\frac{1}{2}$
Question 3 Explanation:
$\displaystyle \begin{array}{l}=\frac{9}{2}-\left[ \frac{9}{4}\div \left\{ \frac{5}{4}-\frac{1}{2}\left( \frac{3}{2}-\frac{1}{3}-\frac{1}{6} \right) \right\} \right]\\=\frac{9}{2}-\left[ \frac{9}{4}\div \left\{ \frac{5}{4}-\frac{1}{2}\left( \frac{9-2-1}{6} \right) \right\} \right]\\=\frac{9}{2}-\left[ \frac{9}{4}\div \left\{ \frac{5}{4}-\frac{1}{2} \right\} \right]\\=\frac{9}{2}-\left[ \frac{9}{4}\div \left\{ \frac{5-2}{4} \right\} \right]\\=\frac{9}{2}-\left[ \frac{9}{4}\div \frac{3}{4} \right]\\=\frac{9}{2}-\frac{9}{4}\times \frac{4}{3}\\=\frac{9}{2}-3\\=\frac{3}{2}\\=1\frac{1}{2}\end{array}$
 Question 4
$\displaystyle \frac{5}{8}\,\,of\,\,\frac{2}{3}\,\,of\,\frac{3}{7}\,\,of\,\,22=?$
 A 42/14 B 43/14 C 39/14 D 55/14
Question 4 Explanation:
$\displaystyle \begin{array}{l}?=\frac{5}{8}\,\,of\,\,\frac{2}{3}\,\,of\,\,\frac{3}{7}\,\,of\,\,22\\=\frac{5}{8}\times \frac{2}{3}\times \frac{3}{7}\times 22=\frac{55}{14}\end{array}$
 Question 5
$\displaystyle \left[ {{\left( 165 \right)}^{2}}\div 75\times 12 \right]\div 24=\left( ? \right)$
 A 13 B 169 C 121 D none
Question 5 Explanation:
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