• This is an assessment test.
  • These tests focus on the basics of Maths and are meant to indicate your preparation level for the subject.
  • Kindly take the tests in this series with a pre-defined schedule.

Basic Maths: Test 26

Congratulations - you have completed Basic Maths: Test 26.You scored %%SCORE%% out of %%TOTAL%%.You correct answer percentage: %%PERCENTAGE%% .Your performance has been rated as %%RATING%%
Your answers are highlighted below.
Question 1
$ \displaystyle 402.46+495.72-423.47=?$
A
576.77
B
547.17
C
547.77
D
474.71
Question 1 Explanation: 
$ \displaystyle \begin{array}{l}402.46+495.72-423.47=?\\=898.18-423.47=474.71\end{array}$
Question 2
$ \sqrt[3]{5832}\div \sqrt[3]{216}=\sqrt[3]{?}$
A
16
B
8
C
27
D
4
Question 2 Explanation: 
$ \displaystyle \begin{array}{l}\sqrt[3]{?}=\sqrt[3]{5832}\div \sqrt[3]{216}\\=\sqrt[3]{18\times 18\times 18}\div \sqrt[3]{6\times 6\times 6}\\=18\div 6=3\\Therefore\,\,\,p=3\times 3\times 3=27\end{array}$
Question 3
?% of 400 = 293-22% of 750
A
24
B
32
C
22
D
26
Question 3 Explanation: 
$ \displaystyle \begin{array}{l}\frac{400\times ?}{100}=293-\frac{750\times 22}{100}\\\Rightarrow 4\times ?=293-165=128\\\Rightarrow ?=\frac{128}{4}=32\end{array}$
Question 4
$ \displaystyle 273\div 7-9.1=p$
what is the value of p
A
29.9
B
22.3
C
24.9
D
21.8
Question 4 Explanation: 
$ \displaystyle p=\frac{273}{7}-9.1=39-9.1=29.9$
Question 5
$ \displaystyle \sqrt{3969}\div 0.7=?\times 2.5$
A
18
B
36
C
16
D
24
Question 5 Explanation: 
$ \displaystyle \begin{array}{l}\sqrt{3969}\div 0.7=?\times 2.5\\\Rightarrow 63\times \frac{1}{0.7}=?\times 2.5\\\Rightarrow ?=\frac{63}{0.7\times 2.5}=36\end{array}$
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