- This is an assessment test.
- These tests focus on the basics of Maths and are meant to indicate your preparation level for the subject.
- Kindly take the tests in this series with a pre-defined schedule.

## Basic Maths: Test 28

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*Basic Maths: Test 28*.You scored %%SCORE%% out of %%TOTAL%%.You correct answer percentage: %%PERCENTAGE%% .Your performance has been rated as %%RATING%% Your answers are highlighted below.

Question 1 |

$ \frac{4\frac{3}{8}-\frac{1}{2}}{3\frac{2}{3}+2\frac{1}{7}}\div \frac{1}{3+\frac{3}{3+\frac{1}{3-\frac{1}{3}}}}$

is equal to

is equal to

$ \frac{7699}{2928}$ | |

$ \frac{7595}{2928}$ | |

$ \frac{75}{2928}$ | |

$ \frac{759}{2928}$ |

Question 1 Explanation:

Question 2 |

$ If\,\,{{\left[ 4-\frac{5}{3-\frac{1}{\frac{5}{9}+\frac{1}{2+\frac{1}{4}}}} \right]}^{th}}$

part of a journey takes 10 minutes, then to compete 6/5th of that journey, it will take

part of a journey takes 10 minutes, then to compete 6/5th of that journey, it will take

3 minutes | |

13 minutes | |

24 minutes | |

8 minutes |

Question 2 Explanation:

We are given by a fraction which is a part of any Distance

First we will solve that fraction part then we will proceed for the further question

$ \displaystyle \begin{array}{l}4-\frac{5}{3-\frac{1}{\frac{5}{9}+\frac{1}{\frac{9}{4}}}}=4-\frac{5}{3-\frac{1}{\frac{5}{9}+\frac{4}{9}}}\\=4-\frac{5}{3-1}=4-\frac{5}{2}\\=\frac{8-5}{2}\\=\frac{3}{2}\\Time\,\,\,taken\,\,in\,\,\,completing\,\,\,=10\,\,\min utes\\Therefore\,\,\,time\,\,taken\,\,\,in\,\,\,completing\,\,\frac{6}{5}\,\,part\\=10\times \frac{2}{3}\times \frac{6}{5}\\=8\,\,Minutes\end{array}$

First we will solve that fraction part then we will proceed for the further question

$ \displaystyle \begin{array}{l}4-\frac{5}{3-\frac{1}{\frac{5}{9}+\frac{1}{\frac{9}{4}}}}=4-\frac{5}{3-\frac{1}{\frac{5}{9}+\frac{4}{9}}}\\=4-\frac{5}{3-1}=4-\frac{5}{2}\\=\frac{8-5}{2}\\=\frac{3}{2}\\Time\,\,\,taken\,\,in\,\,\,completing\,\,\,=10\,\,\min utes\\Therefore\,\,\,time\,\,taken\,\,\,in\,\,\,completing\,\,\frac{6}{5}\,\,part\\=10\times \frac{2}{3}\times \frac{6}{5}\\=8\,\,Minutes\end{array}$

Question 3 |

$ \left( 1001\frac{1001}{1000}\times 7 \right)$

is equals to

is equals to

$ 6998\frac{1}{1000}$ | |

$ 7008\frac{7}{1000}$ | |

$ 7003\frac{1}{1000}$ | |

$ 7014\frac{7}{1000}$ |

Question 3 Explanation:

$ \begin{array}{l}1001\frac{1001}{1000}\times 7\\=\left( 1001+\frac{1001}{1000} \right)\times 7\\=7007+\frac{7007}{1000}\\=7007+7\frac{7}{1000}\\=7014\frac{7}{1000}\end{array}$

Question 4 |

$ \sqrt{\frac{15\frac{1}{8}-\frac{38}{16}}{5+\frac{1}{4}+1\frac{1}{8}}\div \frac{179}{3+\frac{1}{3+\frac{1}{6-\frac{1}{3}}}}}$

is equal to

is equal to

$ \frac{1}{3\sqrt{3}}$ | |

$ 3\sqrt{3}$ | |

$ 3$ | |

$ \sqrt{3}$ |

Question 4 Explanation:

Question 5 |

The sum ‘9+…..+19’ is equal to:

150 | |

160 | |

154 | |

164 |

Question 5 Explanation:

$ \begin{array}{l}1+2+3+.....+n=\frac{n\left( n+1 \right)}{2}\\Therefore\,9+10+11+....+19\\=\left( 1+2+3+.....+19 \right)-\left( 1+2+3....+8 \right)\\=\frac{19\left( 19+1 \right)}{2}-\frac{8\left( 8+1 \right)}{2}=190-36=154\end{array}$

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