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Basic Maths: Test 4

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Question 1
54.5% of 600 + 30.5% of 1800 = (p)2+200
A
+36 or -36
B
+26 or -26
C
–81 or +81
D
none
Question 1 Explanation: 
$ \displaystyle \begin{array}{l}\frac{54.5\times 600}{100}+\frac{30.5\times 1800}{100}={{p}^{2}}+200\\\Rightarrow 327+549={{p}^{2}}+200\\\Rightarrow 876={{p}^{2}}+200\\\Rightarrow {{p}^{2}}=876-200=676\\Therefore\,\,p=\sqrt{676}=\pm 26\end{array}$
Question 2
$ \displaystyle \sqrt{{{7}^{2}}\times 6+\left( {{15}^{2}} \right)+57}=p$
A
24
B
(519)1/2
C
519
D
529
Question 2 Explanation: 
$ \displaystyle \begin{array}{l}p=\sqrt{49\times 6+225+57}\\=\sqrt{294+225+57}\\=\sqrt{576}=24\end{array}$
Question 3
Find the value of p? $ \displaystyle \sqrt{625.04}\times 16.94+204.001\div 17=p$
A
4.18
B
4.41
C
425
D
437
Question 3 Explanation: 
Taking approximate values
$ \displaystyle \begin{array}{l}p=\sqrt{625}\times 17+204\div 17\\=25\times 17+204\times \frac{1}{17}\\=425+12=437\end{array}$
Question 4
$ \displaystyle 0.34\overline{33}+0.13\overline{33}=?$
A
$ \displaystyle 0.47$
B
$ \displaystyle 0.47\overline{66}$
C
$ \displaystyle 0.\overline{48}$
D
$ \displaystyle 4.\overline{8}$
Question 4 Explanation: 
$ \displaystyle \begin{array}{l}0.34\overline{33}+0.13\overline{33}\\=\frac{3433-34}{9900}+\frac{1333-13}{9900}\\=\frac{3399+1320}{9900}=\frac{4719}{9900}\\=\frac{4766-47}{9900}=0.47\overline{66}\end{array}$
Question 5
28.217 – 14.241 + 6.873 – 2.434 =p
A
9.419
B
18.545
C
16.275
D
none
Question 5 Explanation: 
$ \displaystyle p=28.217-14.241+6.873-2.434=18.415$
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