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• This is an assessment test.
• These tests focus on the basics of Maths and are meant to indicate your preparation level for the subject.
• Kindly take the tests in this series with a pre-defined schedule.

## Basic Maths: Test 47

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 Question 1
$3.5\overline{625}$ is equal to
 A $3\frac{4394}{995}$ B $3\frac{292}{333}$ C $3\frac{562}{999}$ D $3\frac{878}{999}$
Question 1 Explanation:
\begin{align} & 3.5\overline{625}=\frac{35625-35}{9990} \\ & =\frac{35590}{9990}=3\frac{562}{999} \\ \end{align}
 Question 2
$0.65\times 6.5-2\times 6.5\times 0.35+0.35\times 3.5$ is equal to
 A 9 B 90 C 9.9 D 0.9
Question 2 Explanation:
Expression
\begin{align} & 0.65\times 6.5-2\times 6.5\times 0.35+0.35\times 3.5 \\ & =0.65\times 0.65\times 10-2\times 0.65\times 0.35\times 10+0.35\times 0.35\times 10 \\ & =10\left( {{\left( 0.65 \right)}^{2}}-2\times 0.65\times 0.35+{{\left( 0.35 \right)}^{2}} \right) \\ & =10{{\left( 0.65-0.35 \right)}^{2}} \\ & =10\times 0.09 \\ & =0.9 \\ \end{align}
 Question 3
$\frac{{{\left( 7.89 \right)}^{2}}-{{\left( 4.56 \right)}^{2}}}{7.89+4.56}$ is simplified to
 A 3.3 B 3.33 C 3.23 D 3.26
Question 3 Explanation:
Let 7.89= a and 4.56 = b
Therefore expression
\begin{align} & =\frac{{{a}^{2}}-{{b}^{2}}}{a+b} \\ & =\frac{\left( a-b \right)\left( a+b \right)}{a+b} \\ & =a-b=7.89-4.56=3.33 \\ \end{align}
 Question 4
A sum of Rs.27.15 is made of 170 coins which are either 10 paise coins of 25 paise coins. The number of 10 paise coins is:
 A 119 B 125 C 109 D 96
Question 4 Explanation:
Let the number of 10 paise coins be x
Number of 25 paise coins = 180 - x
According to the question,
\begin{align} & x\times 10+25\,\,\left( 170-x \right) \\ & =27.15\times 100 \\ & \Rightarrow 10x+4250-25x=2715 \\ & \Rightarrow 15x=4500-2715=1785 \\ & \Rightarrow x=\frac{1785}{15}=119 \\ & \therefore \,\,Number\,\,\,of\,\,10\,\,paise\,\,coins\,\,\,=119 \\ \end{align}
 Question 5
(25)3÷ (5)2 =?
 A 5 B 625 C 125 D 25
Question 5 Explanation:
$?=\frac{25\times 25\times 25}{5\times 5}=625$
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