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Basic Maths: Test 53
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Question 1 
Rahul's monthly salary is one and a half times Harsh's monthly salary, Nikhil's monthly salary is fivefourth of Rahul's monthly salary. If the total of the monthly salaries of all the three is Rs.1.83,750. what is Nikhil's monthly salary?
Rs.42,000  
Rs.68,500  
Rs.78,750
 
Rs.63,000 
Question 1 Explanation:
$\begin{align}
& Let\,\,\,Harsh's\,\,\,monthly\,\,\,income\,\,be\,\,Rs.\,x. \\
& Rahul's\,\,\,monthly\,\,\,income\,\,=Rs.\,\frac{3x}{2} \\
& Nikhil's\,\,monthly\,\,\,income\,\,=Rs.\,\frac{15x}{8} \\
& Therefore\,\,x+\frac{3x}{2}+\frac{15x}{8}=183750 \\
& \Rightarrow \frac{8x+12x+15x}{8}=183750 \\
& \Rightarrow 35x=183750\times 8 \\
& \Rightarrow x=\frac{183750\times 8}{35}=42000 \\
& Therefore\,\,Nikhil's\,\,\,monthly\,\,\,\,income\, \\
& =Rs.\,\left( \frac{15}{8}\times 42000 \right) \\
& =Rs.78750 \\
\end{align}$
Question 2 
$\left( 41\times 71+123\times 23+82\times 25 \right)$ is equal to
779000
 
7090  
7790  
70900 
Question 2 Explanation:
$\begin{align}
& =\left( 41\times 71+123\times 23+82\times 25 \right) \\
& =41\,\left( 71+3\times 23+2\times 25 \right) \\
& =41\,\left( 71+69+50 \right) \\
& =41\times 190=7790 \\
\end{align}$
Question 3 
$\left( \frac{3.77\times 3.77\times 3.771.77\times 1.77\times 1.77}{3.77\times 3.77+3.77\times 1.77+1.77\times 1.77} \right)$ is equal to
âˆ’2  
0.2  
âˆ’0.2  
2

Question 3 Explanation:
Let 3.77 = a
And 1.77= b
Therefore expression
$\begin{align} & =\frac{{{a}^{3}}{{b}^{3}}}{{{a}^{2}}+ab+{{b}^{2}}} \\ & =ab=3.771.77=2.0 \\ \end{align}$
And 1.77= b
Therefore expression
$\begin{align} & =\frac{{{a}^{3}}{{b}^{3}}}{{{a}^{2}}+ab+{{b}^{2}}} \\ & =ab=3.771.77=2.0 \\ \end{align}$
Question 4 
$5\frac{2}{71}\times 9\frac{12}{17}\times 12\frac{10}{11}+4\frac{3}{4}=?$
603.75
 
635.75  
634.75  
605.75 
Question 4 Explanation:
$\begin{align}
& ?=\frac{357}{71}\times \frac{165}{17}\times \frac{142}{11}+4.75 \\
& =630+4.75=634.75 \\
\end{align}$
Question 5 
386  
312  
314  
320

Question 5 Explanation:
$\begin{align}
& 7512\times \frac{5}{38}\times \frac{95}{100}=?+619 \\
& \Rightarrow 939=?+619 \\
& \Rightarrow ?=939619=320 \\
\end{align}$
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