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• This is an assessment test.
• These tests focus on the basics of Maths and are meant to indicate your preparation level for the subject.
• Kindly take the tests in this series with a pre-defined schedule.

## Basic Maths: Test 6

Congratulations - you have completed Basic Maths: Test 6. You scored %%SCORE%% out of %%TOTAL%%. You correct answer percentage: %%PERCENTAGE%% . Your performance has been rated as %%RATING%%
 Question 1
What is the value of p ?
$\displaystyle \frac{p}{\sqrt{130}}=\frac{\sqrt{170}}{p}$
 A 196 B 12 C 144 D 16
Question 1 Explanation:
$\displaystyle \begin{array}{l}\frac{p}{\sqrt{130}}=\frac{\sqrt{170}}{p}\\{{\left( p \right)}^{2}}=\sqrt{130}\times \sqrt{170}\\=11.40\times 13.03=148.542\\p=\sqrt{148.542}\approx 12\end{array}$
 Question 2
$\displaystyle If\,\,\,\,1.5p=0.04q$,then the value of $\displaystyle \left( \frac{q-p}{q+p} \right)\,\,is:$
 A 730/77 B 73/77 C 7.3/77 D 703/77
Question 2 Explanation:
$\displaystyle \begin{array}{l}1.5p=0.04q\\\Rightarrow \frac{p}{q}=\frac{0.04}{1.5}=\frac{4}{150}=\frac{2}{75}\\\therefore \,\,Expression\,\,=\frac{q-p}{q+p}=\frac{1-\frac{p}{q}}{1+\frac{p}{q}}\\=\frac{1-\frac{2}{75}}{1+\frac{2}{75}}=\frac{\frac{75-2}{75}}{\frac{75+2}{75}}\\=\frac{73}{75}\times \frac{75}{77}=\frac{73}{77}\end{array}$
 Question 3
If $\displaystyle {{2}^{2p-1}}=\frac{1}{{{8}^{p-3}}}$,then the value of p is:
 A –1 B –2 C 2 D 3
Question 3 Explanation:
$\displaystyle \begin{array}{l}{{2}^{2p-1}}=\frac{1}{{{8}^{p-3}}}={{8}^{-\left( p-3 \right)}}\\\Rightarrow {{2}^{2p-1}}={{8}^{3-p}}={{\left( {{2}^{3}} \right)}^{\left( 3-p \right)}}\\\Rightarrow {{2}^{2p-1}}={{2}^{9-3p}}\\\Rightarrow 2p-1=9-3p\\\Rightarrow 2p+3p=9+1\\\Rightarrow 5p=10\\\Rightarrow p=\frac{10}{5}=2\end{array}$
 Question 4
$\displaystyle 36865+12473+21045-44102=p$
 A 114485 B 28081 C 26281 D 114845
Question 4 Explanation:
$\displaystyle \begin{array}{l}p=36865+12473+21045-44102\\=70383-44102=26281\end{array}$
 Question 5
$\displaystyle 5328\times \frac{3}{4}\times \frac{2}{9}\times p=619$
 A 0.69 B 1.5 C 0.2 D 2.4
Question 5 Explanation:
$\displaystyle \begin{array}{l}5328\times \frac{3}{4}\times \frac{2}{9}\times p=619\\\Rightarrow 888\times p=619\\\Rightarrow p=\frac{619}{888}=0.69\end{array}$
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