# FACTORS

In this article we shall study more about factors. Hence, we’ll learn how to calculate the number of factors ending with zero, factors not ending with zero and factors divisible by various numbers(for eg: 12).

Factors that end with zero:

Factors whose unit digit is zero are the factors that are divisible by 10.

Example: Find the number of factors of 58800 that end with 0.

Solution:

We first factorize 58800.

58800 = 24 315272

We basically need to find the factors that are divisible by 10. If a number ends with 0 then it must have at least one pair of 21 and 51.

Here, we won’t consider . Now, calculate number of factors by making combinations.

2(1 or 2 or 3or 4)—– 4 factors

3(0 or 1 )    —– 2 factors

5(1 or 2) ——- 2 factors

7(0 or 1 or 2) — 3 factors

Hence, total number of factors ending with 0 = (4)(2)(2)(3) = 48

Factors not ending with zero

Example: Find the number of factors of 58800 that are not ending with 0.

Solution: We first factorize 58800.

58800 = 24 315272

Total number of factors of 58800 is 5x2x3x3=90 and in previous example we calculated total number of factors ending with 0 are 48.

Number of factors not ending with 0 = Total number of factors – Number of factors ending with 0

=90- 48 =42.

Factors divisible by 12:

Example: Find the number of factors of 58800, which are divisible by 12.

Solution:

Since we have to find the number of factors which are divisible by 12, then it must

have at least 22 and 31. So we will not consider

We first factorize 58800.

58800 = 24 315272

Hence factors divisible by 12 must have

2(2 or 3or 4)—– 3 factors

3( 1 )     —–   1  factor

5(0 or1 or 2) ——- 3 factors

7(0 or 1 or 2) — 3 factors

Hence, total number of factors, which are divisible by 12 = (3)(1)(3)(3) = 27

NOTE: To find the number of factors that are divisible by any composite factors, the maximum power in divisor must be present in the dividend.

To be thorough with these types of questions, solve the given exercise.

EXERCISE:

Question 1: Find the number of factors of 58800, which are divisible by 98.

(1) 12

(2) 10

(3) 6

(4) 18

Solution: Option 1

We first factorize 58800.

58800 = 24 315272

Since we have to find the number of factors, which are divisible by 98 , then it must

have at least 72 and 21. So we will not consider .

Hence factors divisible by 98 must have

2(1 or 2 or 3or 4)—– 4 factors

3( 0 or 1 )     —–   2  factors

5(0 or1 or 2) ——- 3 factors

7( 2) ———– =1 factor

Hence, total number of factors, which are divisible by 98 = > (4)(1)(3)(1) = 12

Question 2:  Find the number of factors of 4200, which are divisible by 125.

(1) 5

(2) 1

(3) 2

(4) 0

Solution: Option 4

We first factorize 4200 = 23 315271

Since we have to find the number of factors, which are divisible by 125 , then it must

have at least 53 .

But we can see that there is no 53 . So no factor is divisible by 125.

Question 3. Find the number of factors of 600 that end with 0.

(1) 8

(2) 12

(3) 16

(4) 24

Solution: Option 2

Prime factorization of 600 i.e. 600= 233152

We basically need to find the factors which are divisible by 10 . If a number ends with 0 then it must have atleast one pair of 21 and 51.

So we won’t consider 20 and 50. Now calculate number of factors by making combinations.

2(1 or 2 or 3)—– 3 factors

3(0 or 1 )     —– 1+1=2 factors

5(1 or 2) ——- 2 factors

Hence, total number of factors ending with 0 = (3)(2)(2) = 12

Question 4. Find the number of factors of 600 that do not end with 0.

(1) 8

(2) 12

(3) 16

(4) 24

Solution: Option 2

Solution:

Prime factorization of 600 i.e. 600= 233152

Total number of factors = (3+1)*(1+1)*(2+1)=24

Total number of factors ending with 0 = (3)(2)(2) = 12    { as we calculated in previous question }

Number of factors not ending with 0 = Total number of factors – Number of factors ending with 0

Number of factors not ending with 0= 24-12= 12