We all have studied about basic division concepts. In this article, we will further extend this concept to understand factors and multiples.
Factors:
If an integer x is completely divided by another integer y, then x is said to be a multiple of y; and y is said to be a factor of x.
Let us take an example to understand it better.
Example:
12 is a multiple of 3 as it divides 12 four times and 3 is a factor of 12.
But 12 cannot be a multiple of 7 as 12 cannot be divided by 7 completely.
Next we move on to the calculation of the total number of factors.
Total Number of Factors of a Number:
A composite number N can be written as a product of its prime factors.
If N can be written as
(Where a, b, c are prime numbers)
But where did this formula come from? Let us understand by taking an example.
Example: Take N = 300
Prime factors of N=
Now if a number D is to divide N, maximum value of D can be =
Now that we have calculated the total number of factor, let us see how many of those are even and how many are odd.
Finding ODD and EVEN Factors of a Number:
Even Factors:
Example: Let us take an example of N = 240
N= 240=
To make any factor EVEN, 2 or any of its power has to be a multiple of it, otherwise odd*odd can give a odd number. For eg:
2*3=6; *5=20 are even factors, because they are getting multiplied with 2 or with its powers.
But in case we don’t include 2, then
3*5 =15 ; *5 = 5
So, if even factors are to be calculated we need to exclude and include all other powers of 2 while making combinations.
Let D be a possible factor of N, then
D=
In this case, total no of even factors will be = 4 * (1+1)*(1+1) = 16
Odd factors:
Again we will take example of N= 240
Unlike the above-discussed solution, in this case only power included of 2 will be
So N= 240=
Odd factors :- 1*(1+1)*(1+1)=4
With everything studied so far, you need to keep the following in mind:
NOTE 1:
We know that total no. of factors of 240 will be= 5*2*2=20
Using
In this case =>
Total no of factors = even factors + odd factors
20= 16+4
So after calculating even factors we can subtract them from total number of factors to get number of odd factors.
NOTE 2:
Keep in mind that number of odd factors won’t be equal to the number of even factors. Usually we tend to take the number of odd/even factors as half of the total number of factors. But that won’t be the case.
Let’s try some questions based on the above-discussed concepts.
EXERCISE:
Question 1: Find the total number of factors of 58800.
(1) 90
(2) 80
(3) 180
(4) 45
Answer and Explanation
Solution: option (1)
We first factorize 58800.
58800 = 24 315272
Total number of factors = (4+1)(1+1)(2+1)(2+1)=90
Question 2: Find the number of even factors of 58800.
(1) 90
(2) 72
(3) 18
(4) 45
Answer and Explanation
Solution: option (2)
We first factorize 58800.
58800 = 24 315272
To calculate even factors we exclude 20
So total, number of even factors will be= (4)(1+1)(2+1)(2+1)=72
Question 3: Find the number of odd factors of 58800.
(1) 90
(2) 72
(3) 18
(4) 45
Answer and Explanation
Solution: option (3)
We first factorize 58800.
58800 = 24 315272
Number of odd factors = total no of factors – number of even factors
Number of odd factors = 90 -72 = 18
Question 4: Find the number of even factors of 840.
(1) 32
(2) 72
(3) 24
(4) 48
Answer and Explanation
Solution: Option (3)
We first factorize 840.
To calculate even factors we exclude 20
So total, number of even factors will be= (3)(1+1)(1+1)(1+1)=24
Question 5: Find the number of odd factors of 840.
(1) 8
(2) 7
(3) 18
(4) 32
Answer and Explanation
Solution: Option (1)
We first factorize 58800.
Total no of factors = 4*2*2*2=32
Number of odd factors = total no of factors – number of even factors
Number of odd factors = 32-24 = 8