• This is an assessment test.
  • To draw maximum benefit, study the concepts for the topic concerned.
  • Kindly take the tests in this series with a pre-defined schedule.

Geometry and Mensuration: Level 1 Test 1

Congratulations - you have completed Geometry and Mensuration: Level 1 Test 1.You scored %%SCORE%% out of %%TOTAL%%.You correct answer percentage: %%PERCENTAGE%% .Your performance has been rated as %%RATING%%
Your answers are highlighted below.
Question 1
The area of circle is seven times the numerical value of its circumference. What is the circumference of the circle? 
A
616 units
B
132 units
C
88 units
D
Cannot be determined
Question 1 Explanation: 
Let the radius of the circle be r units.
$ \begin{array}{l}\pi {{r}^{2}}=7\times 2\pi r\\=>r=14\\=>2\pi r=\frac{2\times 22}{7}\times 14=88units\\Correct\,\,option\,\,is\,\,(c)\end{array}$
Question 2
AD is the median of a triangle ABC and O is the centroid such that AO= 10 cm. The length of OD in cm is
A
4
B
5
C
6
D
8
Question 2 Explanation: 
64
AO = 10 cm. Therefore ,
AD= 3/2 AO = 15 cm.
OD = 1/3 AD = 1/3 x 15 cm = 5 cm.
Question 3
What will be the cost of gardening 1 metre broad boundary around a rectangular plot having perimeter of 340 metres at the rate of Rs.10 per square metre?
A
Rs.3, 400/-
B
Rs.1, 700/-
C
Rs.3, 440/-
D
Cannot be determined
Question 3 Explanation: 
Let the length be l and breadth be b units.
Area of the boundary= lb+2(l+b)+4-lb
= 2(l+b) +4 =344
The total cost = 344 x 10 = Rs. 3440
Correct option is (c)
Question 4
If ΔABC is an isosceles triangle with ∠C= 90o and AC= 5cm, then AB is:
65
A
5 cm
B
10 cm
C
5√2cm
D
2.5 cm
Question 4 Explanation: 
$ \begin{array}{l}AB=\sqrt{2\times {{5}^{2}}}\\AB=5\sqrt{2}\\The\,\,correct\,\,option\,\,is\,\,c\end{array}$
Question 5
The ratio of the length and the breadth of a rectangular plot is 6:5 respectively. If the breadth of the plot is 34 metres less than the length, what is the perimeter of the rectangular plot?
A
374 metres
B
408 metres
C
814 metres
D
748 metres
Question 5 Explanation: 
$ \displaystyle \begin{array}{l}Let\text{ }the\text{ }plot\text{ }be\text{ }of\text{ }length\text{ }and\text{ }breadth\text{ }6x\text{ }and\text{ }5x\text{ }units\text{ }resp.\\6x-5x\text{ }=\text{ }34.\\Thus\text{ }the\text{ }perimeter\text{ }=\text{ }2x\text{ }\left( 5x+6x \right)\text{ }\times ~34\text{ }=\text{ }22\times 34\text{ }=748\text{ }cm.\end{array}$
Once you are finished, click the button below. Any items you have not completed will be marked incorrect. Get Results
There are 5 questions to complete.
List
Return
Shaded items are complete.
12345
End
Return



Pin It on Pinterest