Geometry and Mensuration: Level 1 Test 1

Let the radius of the circle be r units.
$ \begin{array}{l}\pi {{r}^{2}}=7\times 2\pi r\\=>r=14\\=>2\pi r=\frac{2\times 22}{7}\times 14=88units\\Correct\,\,option\,\,is\,\,(c)\end{array}$

AO = 10 cm. Therefore ,
AD= 3/2 AO = 15 cm.
OD = 1/3 AD = 1/3 x 15 cm = 5 cm.

Let the length be l and breadth be b units.
Area of the boundary= lb+2(l+b)+4-lb
= 2(l+b) +4 =344
The total cost = 344 x 10 = Rs. 3440
Correct option is (c)

$ \begin{array}{l}AB=\sqrt{2\times {{5}^{2}}}\\AB=5\sqrt{2}\\The\,\,correct\,\,option\,\,is\,\,c\end{array}$

$ \displaystyle \begin{array}{l}Let\text{ }the\text{ }plot\text{ }be\text{ }of\text{ }length\text{ }and\text{ }breadth\text{ }6x\text{ }and\text{ }5x\text{ }units\text{ }resp.\\6x-5x\text{ }=\text{ }34.\\Thus\text{ }the\text{ }perimeter\text{ }=\text{ }2x\text{ }\left( 5x+6x \right)\text{ }\times ~34\text{ }=\text{ }22\times 34\text{ }=748\text{ }cm.\end{array}$