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Geometry and Mensuration: Level 2 Test 4
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Question 1 |
$ \displaystyle \begin{array}{l}Suppose\,\vartriangle ABC\text{ }be\text{ }a\text{ }right-angled\text{ }triangle\text{ }where\,\angle A=\text{ }{{90}^{o}}and\,AD\bot BC.\text{ }\\If\,\vartriangle ABC=\text{ }40\text{ }c{{m}^{2}},\vartriangle ACD=\text{ }10\text{ }c{{m}^{2}}and\,\,\overline{AC}=\text{ }9\text{ }cm,\text{ }\\then\text{ }the\text{ }length\text{ }of\text{ }BC\text{ }is\end{array}$
12 cm | |
18 cm | |
4 cm | |
6 cm |
Question 1 Explanation:
The area of ABD = 40-10 = 30 .
Therefore,AB2= (92x30)/10 = 243
Thus
BC2 =243 +81 =325
Therefore BC = 18 approx
Therefore,AB2= (92x30)/10 = 243
Thus
BC2 =243 +81 =325
Therefore BC = 18 approx
Question 2 |
If length of the rectangle is increased by 50% and breadth is decreased by 20%. Then what is the percentage change in the area?
By decrease 20% | |
20% increase | |
80% increase | |
30% decrease |
Question 2 Explanation:
The new rectangle is 1.5 x 0.8 = 1.2 of the previous rectangle.Thus the increase in area = 20 %
Correct option is (b)
Question 3 |
The length and breadth of the floor of a room are 20 feet and 10 feet respectively. Square tiles of 2 feet length of three different colours are to be laid on the floor. Black tiles are laid in the first row on all sides. If white titles are laid in the one-third of the remaining and blue tiles in the rest, how many blue tiles will be there?
16 | |
32 | |
48 | |
24 |
Question 3 Explanation:
Area covered by blue and white tiles = (20-4)(10-4) = 16 x 6 sq. ft.
The area covered by the blue tiles = (16 x 6 x 2)/3 = 64 ft2The total number of blue tiles= 64/4 = 16
Correct option is (a)
Question 4 |
The sum of the interior angles of a polygon is 1620o. The numbers of sides of the polygon are
9 | |
11 | |
15 | |
12 |
Question 4 Explanation:
180 (no. of sides -2 ) = 1620
=> No of sides = (162 /18)+2
=> No of sides = 11.
Correct option is (b)
=> No of sides = (162 /18)+2
=> No of sides = 11.
Correct option is (b)
Question 5 |
In a triangle ABC, BAC= 90o and AD is perpendicular to BC. If AD= 6 cm and BD = 4cm, then the length of BC is
8 cm | |
10 cm | |
9 cm | |
13 cm |
Question 5 Explanation:
$ \displaystyle \begin{array}{l}Let\,\,DC=x\,\,\,cm\\AB=\sqrt{52}\,\,by\,\,pythagoras\,\,Theorem\,\,\\{{(4+x)}^{2}}={{(4+x)}^{2}}=\sqrt{{{6}^{2}}+{{x}^{2}}}+52\\x=9\\Thus\,\,BC=9+4=13cm\end{array}$
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