• This is an assessment test.
  • To draw maximum benefit, study the concepts for the topic concerned.
  • Kindly take the tests in this series with a pre-defined schedule.

Geometry and Mensuration: Level 2 Test 5

Congratulations - you have completed Geometry and Mensuration: Level 2 Test 5.You scored %%SCORE%% out of %%TOTAL%%.You correct answer percentage: %%PERCENTAGE%% .Your performance has been rated as %%RATING%%
Your answers are highlighted below.
Question 1
In a cyclic quadrilateral ABCD, ∠A is double its opposite angle and the difference between the other two angles is one-third of ∠A. The minimum difference between any two angles of this quadrilateral is
A
30o
B
10o
C
20o
D
40o
Question 1 Explanation: 
Let ∠A be equal to 2x.
Thus 2+x= 180,
=> x=60.
Thus, Two angles are 60 and 120.
Difference between the other two angles = 1/3 of 120 = 40
Sum of the two angles = 180.
Thus the two angles = 110 and 70 degrees.
Thus The difference between any two angles  will be minimum for 110 and 120 = 10o
Correct option is (b)
Question 2
Inside a triangle ABC, a straight line parallel to BC intersects AB and AC at the points P and Q respectively. If AB= 3 PB, then PQ: BC is
A
1: 3
B
3: 4
C
1: 2
D
2: 3
Question 2 Explanation: 
Since AB= 3 PB. Therefore, AP:PB = 2:1.
Thus PQ:BC= 2/(2+1)=2:3
The correct option is (d)
Question 3
The area of a rectangular field is 460 square metres. If the length is 15 per cent more than the breadth, what is breadth of the rectangular field?
A
15 metres
B
26 metres
C
34.5 metres
D
none
Question 3 Explanation: 
Let the breadth be x m Thus the length = 1.15x m
Thus, 1.15x2 = 460
x =√400
x = 20
Question 4
ABCD is a square, F is mid-point of AB and E is a point on BC such that BE is one-third of BC. If area of ΔFBE = 108 m2, then the length of AC is  
A
60 m
B
$ \displaystyle 36\sqrt{2}$
C
$ \displaystyle 63\sqrt{2}$
D
$ \displaystyle 72\sqrt{2}$
Question 4 Explanation: 
Let the length of each side of square be 6x.
Thus FB = 3x and BE = 2x.
Area = ½ (3x)(2x) = 3x2= 108
x = 6
Thus the diagonal AC= 6 x 6√2 = 36√2 m
Question 5
Inside a square plot a circular garden is developed which exactly fits in the square plot and the diameter of the garden is equal to the side of the square plot which is 28 metres. What is the area of the space left out in the square plot after developing the garden?
A
98 m2
B
146 cm2
C
84 m2
D
168 m2
Question 5 Explanation: 
The area of the circle = 22/7 x 14 x 14 = 22 x 28 = 616m2
Area of the square = 28x28 = 784 m2
Area left out = 784 - 616 = 168 m2
The correct option is = 168 m2
Once you are finished, click the button below. Any items you have not completed will be marked incorrect. Get Results
There are 5 questions to complete.
List
Return
Shaded items are complete.
12345
End
Return



Pin It on Pinterest