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Geometry and Mensuration: Level 2 Test 9
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Question 1 
Suface area of a cuboid is 22 cm^{2} and the sum of the lengths of all its edges is 24 cm. Length of each diagonal of the cuboid (in cm) is
145  
200  
122  
none 
Question 1 Explanation:
$ \displaystyle \begin{array}{l}Let\text{ }the\text{ }length\text{ },\text{ }width\text{ }and\text{ }height\text{ }be\text{ }l\text{ },\text{ }w\text{ }and\text{ }h\text{ }units\text{ }respectively\\l+b+w=\frac{24}{4}=6\\lb+bw+lw=\frac{22}{2}=11\\Now\,\,{{l}^{2}}+{{b}^{2}}+{{w}^{2}}+2lb+2bw+2lw={{(l+b+w)}^{2}}\\{{l}^{2}}+{{b}^{2}}+{{w}^{2}}+22=36\\{{l}^{2}}+{{b}^{2}}+{{w}^{2}}=14\\\sqrt{{{l}^{2}}+{{b}^{2}}+{{w}^{2}}}=\sqrt{14}\end{array}$
Question 2 
A slab of ice 8 inches in length, 11 inches in breadth, and 2 inches thick was melted and resolidified in the form of a rod of 8 inches diameter. The length of such a rod, in inches, in nearest to:
3  
3·5  
4  
4·5 
Question 2 Explanation:
The volume of the ice slab =8X11X2
The volume of the rod (assuming length = h) =Πx42h = 8 x 11 x 2
h = 3.5
Correct option is (b)
The volume of the rod (assuming length = h) =Πx42h = 8 x 11 x 2
h = 3.5
Correct option is (b)
Question 3 
Four friends start from four towns, which are at the four comers of an imaginary rectangle. They meet at a point which falls inside the rectangle, after travelling the distances of 40 m, 50 m and 60 m. The maximum distance that the fourth could have travelled is approximately:
67 m  
52 m  
22.5 m  
Cannot be determined

Question 3 Explanation:
Now we know that if we assume the length required =p resp,
then 50 x 40 = 60 x p
=> p = 50 x 40/60
=> p = 66.67
The correct option is (a)
then 50 x 40 = 60 x p
=> p = 50 x 40/60
=> p = 66.67
The correct option is (a)
Question 4 
The length of a ladder is exactly equal to the height of the wall it is leaning against. H lower end of the ladder kept on a stool of height 3 m and the stool is kept 9 m away from the wall, the upper end of the ladder coincides with the top of the wall. Then, the height of the wall is:
12 m  
15 m  
18 m  
11 m 
Question 5 
An equilateral triangle and a regular hexagon have equal perimeters. The ratio of the area of the triangle and that of the hexagon is
1: 1  
2: 3  
3: 2  
3: 4 
Question 5 Explanation:
Let the individual sides of the hexagon be 1 cm
Thus the perimeter =6 and the side of the equilateral triangle is 2cm.
Thus the area of the equilateral triangle = √3 x 4 = √3 cm.
Thus the area of the hexagon= {(6 x √3)/4} x 1^{2} = 3/2√3
Thus the ratio of the triangle to hexagon is 2:3.
Correct option is (b)
Thus the perimeter =6 and the side of the equilateral triangle is 2cm.
Thus the area of the equilateral triangle = √3 x 4 = √3 cm.
Thus the area of the hexagon= {(6 x √3)/4} x 1^{2} = 3/2√3
Thus the ratio of the triangle to hexagon is 2:3.
Correct option is (b)
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