Select Page

• This is an assessment test.
• To draw maximum benefit, study the concepts for the topic concerned.
• Kindly take the tests in this series with a pre-defined schedule.

## Geometry and Mensuration: Level 3 Test 6

Congratulations - you have completed Geometry and Mensuration: Level 3 Test 6. You scored %%SCORE%% out of %%TOTAL%%. You correct answer percentage: %%PERCENTAGE%% . Your performance has been rated as %%RATING%%
 Question 1
The length of the common chord of two circles of radii 15 cm and 20 cm whose centers are 25 cm apart, is (in cm):
 A 24 B 25 C 15 D 20
Question 1 Explanation:
$\begin{array}{l}Let\,\,the\,\,total\,\,length\,\,be\,\,2x\,\,units\\\frac{1}{2}x\times 25=\frac{1}{2}\times 15\times 20\\x=12units\\thus\,\,2x=24\,units\\Thus\,\,the\,\,correct\,\,option\,\,is\,\,a\end{array}$
 Question 2
In a triangle ABC, the internal bisector of the angle A meets BC at D. If AB =4, AC= 3 and ∠A= 60o, then, the length of AD is:
 A $\displaystyle 2\sqrt{3}$ B $\displaystyle \frac{12\sqrt{3}}{7}$ C $\displaystyle \frac{15\sqrt{3}}{8}$ D $\displaystyle \frac{6\sqrt{3}}{7}$
Question 2 Explanation:
$\begin{array}{l}let\,\,the\,\,length\,\,of\,\,AD\,\,be\,\,x\,\,units\\\frac{1}{2}\times 4x\times Sin30=\frac{4}{7}\times 4\times 3\times Sin60\\x=\frac{12}{7}\sqrt{3}\\Correct\,\,option\,\,is\,\,b\end{array}$
 Question 3
In the figure (not drawn to scale) given below, P is a point on AB such that AP: PB= 4: 3. PQ is parallel to AC and QD is parallel to CP. In ∠ARC, ∠ARC= 90o, and in ΔPSQ, ∠PSQ= 90o. The length of QS is 6 cms. What is ratio AP: PD?
 A 10: 3 B 2: 1 C 7: 3 D 8: 3
Question 3 Explanation:
$\displaystyle \begin{array}{l}AP:\text{ }PB\text{ }=\text{ }4:3\\Thus\text{ }AP=\text{ }4x\text{ }and\text{ }PB=3x\\Again,\text{ }PD:DB\text{ }=\text{ }CQ:AB\text{ }=\text{ }4:3\\PD=\frac{4}{7}\times BP=\frac{4}{7}\times \frac{3}{4}AP=\frac{3}{7}AP\end{array}$
 Question 4
In the figure (not drawn to scale) given below, if AD = CD = BC, and BCE = 96o, how much is DBC?
 A 32o B 84o C 64o D Cannot be determined
Question 4 Explanation:
Let angle CAD= DCA = x
and thus CDB = 2x and CBD = 2x.
Thus, 180-2x+x+96= 180
=> 2x= 64
Correct option is (c)
 Question 5
In the figure given below (not drawn to scale), A, B and C are three points on a circle with centre O, The chord BA is extended to a points T such that CT becomes a tangent at the circle  at point  C. If ∠ATC= 30o and ∠ACT= 50o, then the angle BOA is:
 A 100o B 150o C 80o D Not possible to determine
Question 5 Explanation:
Since angle ∠CAT = 180-50-30 = 100
By alternate segment theorem ∠ABC = ∠TCA = 50o
Thus ∠ BOA =2{180-50-(180-100)}=100o
Correct option is (a)
Once you are finished, click the button below. Any items you have not completed will be marked incorrect.
There are 5 questions to complete.
 ← List →
 1 2 3 4 5 End
Get Posts Like This Sent to your Email
Updates for Free Live sessions and offers are sent on mail. Don't worry: we do not send too many emails..:)
Get Posts Like This Sent to your Email
Updates for Free Live sessions and offers are sent on mail. Don't worry: we do not send too many emails..:)