• This is an assessment test.
• These tests focus on geometry and mensuration and are meant to indicate your preparation level for the subject.
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## Geometry and Mensuration: Test 29

Congratulations - you have completed Geometry and Mensuration: Test 29. You scored %%SCORE%% out of %%TOTAL%%. You correct answer percentage: %%PERCENTAGE%% . Your performance has been rated as %%RATING%%
 Question 1
The area of a ΔABC is equal to area of square of side length 6 cm. What is the length of the altitude to AB where AB = 9 cm?
 A 18 cm B 14 cm C 12 cm D 8 cm
Question 1 Explanation:
$\begin{array}{l}\frac{1}{2}altitude\times 9=36\\=>altitude=8\end{array}$
 Question 2
What is the area of an equilateral triangle having altitude equal to 2√3 cm?
 A √3 sq cm B 2√3 sq cm C 3√3 sq cm D 4√3 sq cm
Question 2 Explanation:
$\begin{array}{l}Let\text{ }the\text{ }side\text{ }of\text{ }the\text{ }triangle\text{ }=\text{ }x\text{ c}m\\\frac{\sqrt{3}}{4}{{x}^{2}}=\frac{1}{2}\times 2\sqrt{3}x\\=>x=4.\\Area=4\sqrt{3}sq.cm.\end{array}$
 Question 3
A lawn 30m long and 16m wide is surrounded by a path 2 m wide. What is the area of the path?
 A 200 m2 B 280 m2 C 300 m2 D 320 m2
Question 3 Explanation:
 Question 4
A circle circumscribes a rectangle with side 16 cm and 12 cm. What is the area of the circle?
 A 48 π sq cm B 50 π sq cm C 100π sq cm D 200π sq cm
Question 4 Explanation: $\begin{array}{l}The\text{ }diameter\text{ }=\sqrt{{{16}^{2}}+{{12}^{2}}}=\sqrt{400}=20cm\\The\text{ }area\text{ }of\text{ }circle\text{ }=\text{ }100\pi ~sq\text{ }cm.\\Correct\text{ }option\text{ }is\text{ }\left( c \right)\\\end{array}$
 Question 5
The lengths of two sides of a right angled triangle which contain the right angle are ‘a’ and ‘b’ respectively. Three squares are drawn on the three sides of the triangle on the outer side. What is the total area of the triangle and the three squares?
 A 2(a2 + b2) +ab B 2(a2 +b2)+ 2.5 ab C 2(a2 +b2)+ 0.5ab D 2.5 (a2 + b2)
Question 5 Explanation: The total area = a2 +b2+ (a2 +b2) +  1/2ab.
=>  2(a2 +b2)+ 0.5ab The correct option is (c).
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