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- These tests focus on geometry and mensuration and are meant to indicate your preparation level for the subject.
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## Geometry and Mensuration: Test 8

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Question 1 |

The cost of building a fence around a circular field is Rs.7, 700 at the rate of Rs.14 per foot. What is the area of the circular field?(Use π = 22/7)

24062.5 sq. ft. | |

23864.4 sq. ft. | |

24644.5 sq. ft. | |

Cannot be determined |

Question 1 Explanation:

Question 2 |

The total area of a circle and a square is equal to 2611 sq. cm. The diameter of the circle is 42 cms, What is the sum of the circumference of the circle and the perimeter of the square?

272 cms, | |

380 cms, | |

280 cms. | |

Cannot be determined |

Question 2 Explanation:

The area of circle= π x 21

Area of square = 2611 – 1386 = 1225 cm

Sum of the perimeter= {(2x22/7) x 21} +(35 x 4) = 132 + 140 = 272cm

Correct option (a)

^{2}= 441π = 1386 cm^{2}Area of square = 2611 – 1386 = 1225 cm

^{2}. Side of the square = 35 cmSum of the perimeter= {(2x22/7) x 21} +(35 x 4) = 132 + 140 = 272cm

Correct option (a)

Question 3 |

The area of a square is 196 sq. cm. whose side is half the radius of a circle. The circumference of the circle is equal to breadth of a rectangle. If perimeter of the rectangle is 712 cm, what is the length of the rectangle?

196 cm | |

186 cm | |

180 cm | |

190 cm |

Question 3 Explanation:

Side of the square = √196 = 14 cm

Hence the radius of the circle = 28 cm

The circumference of the circle = 2πr = 2 x 22/7 x 28 = 176cm

Hence breadth of the rectangle = 176 cm.

Let 'x' be its length. So we have 2(176 + x) = 712

=> x = 180 cm

Correct option is (c)

Hence the radius of the circle = 28 cm

The circumference of the circle = 2πr = 2 x 22/7 x 28 = 176cm

Hence breadth of the rectangle = 176 cm.

Let 'x' be its length. So we have 2(176 + x) = 712

=> x = 180 cm

Correct option is (c)

Question 4 |

What would be the cost of building a fence around a square plot with area 462.25 sq. ft. at the rate of Rs. 34 per foot?

Rs.2, 924 | |

Rs.2, 682 | |

Rs.2, 846 | |

Cannot be determined |

Question 4 Explanation:

$ \displaystyle \begin{array}{l}Side\text{ }of\text{ }the\text{ }square=\sqrt{462.25}\text{ }=~21.5\text{ }cm\\Total\text{ }cost\text{ }=\text{ }4\text{ }\times \text{ }21.5\text{ }\times \text{ }34\text{ }=\text{ }86\times 34\text{ }=\text{ }Rs.\text{ }2924\\Correct\text{ }option\text{ }is\text{ }\left( a \right)\end{array}$

Question 5 |

The length of a rectangle is twice the diameter of a circle. The circumference of the circle is equal to the area of a square of side 22 cm. What is the breadth of the rectangle if its perimeter is 668 cm?

24 cm | |

26 cm | |

52 cm | |

Cannot be determined |

Question 5 Explanation:

$ \displaystyle \begin{array}{l}Area\text{ }of\text{ }the\text{ }square\text{ }=\text{ }484\text{ }cm\\Circumference=2\pi r=484\\\Rightarrow r=77cm\\Length\text{ }of\text{ }the\text{ }rectangle\text{ }=\text{ }4\times 77\text{ }=\text{ }308\text{ }cm\\Breadth\text{ }=\frac{668}{2}-308=334-308=26cm\end{array}$

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