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## Number System: Level 1 Test -11

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Question 1 |

In a chocolate store, there are vanilla and chocolate flavour bonbons only. 10% of the bonbons are chocolate flavoured, 90% of the rest are squashed. What percentage of the bonbons is vanilla flavoured that are not squashed?

A | 9% |

B | 5% |

C | 1% |

D | 10% |

Question 1 Explanation:

The remaining = 90% of 90% =81 %

Thus left which re vanilla and not squashed = 9%.

Correct option is (a)

Thus left which re vanilla and not squashed = 9%.

Correct option is (a)

Question 2 |

Two times a two-digit number is 9 times the number obtained by reversing the digits and sum of the digits is 9. The number is

A | 72 |

B | 54 |

C | 63 |

D | 81 |

Question 2 Explanation:

Let the number be 10x+y,

20x+2y=90y+9x

=>11x=88y

=>x=8y

x+y=9

Thus the number is 81.

Correct option is (d)

20x+2y=90y+9x

=>11x=88y

=>x=8y

x+y=9

Thus the number is 81.

Correct option is (d)

Question 3 |

If such numbers which are divisible by 5 and also those which have 5 as one of the digits are eliminated from the numbers 1 to 60, how many numbers would remain?

A | 40 |

B | 47 |

C | 53 |

D | 45 |

Question 3 Explanation:

Numbers divisible by 5 are 11 and 9 numbers which have 5 and not divisible by 5.

Thus total to be eliminated = 20.

Remaining = 60-20 =40.

Correct option is (a)

Thus total to be eliminated = 20.

Remaining = 60-20 =40.

Correct option is (a)

Question 4 |

The first 44 positive integers are written in an order to form a larger numberN= 1 2 3 4 5 6 7 9 8 10 11 12……….42 43 44When N is divided by 45, then the remainder is

A | 5 |

B | 7 |

C | 9 |

D | 11 |

Question 4 Explanation:

1+2+...+43+44=(44*45)/2 = 990. Thus the number is divisible by 9.

Now let us consider a number N-9 = 1 2 3 4 5 6 7 9 8 10 11 12……….42 43 35.

Now N-9 is divisible by 9 and 5 i.e. 45.

Thus remainder =9

Correct option is (c)

Now let us consider a number N-9 = 1 2 3 4 5 6 7 9 8 10 11 12……….42 43 35.

Now N-9 is divisible by 9 and 5 i.e. 45.

Thus remainder =9

Correct option is (c)

Question 5 |

If a number of two digits is k times the sum of its digits, then the number formed by interchanging the digits is the sum of the digits multiplied by:

A | 9 + k |

B | 10 + k |

C | 11 – k |

D | k – 1 |

Question 5 Explanation:

Let us check this with a simple number say 12.

12 is 4 (=k) times (1+2)=3

The number formed b interchanged digits is 21.

The sum of the digits = 3.21=3x7

Checking all options only (c) is correct.

12 is 4 (=k) times (1+2)=3

The number formed b interchanged digits is 21.

The sum of the digits = 3.21=3x7

Checking all options only (c) is correct.

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