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Properties of Numbers

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To solve questions based on number system quickly, you should have a good hold of the properties of numbers. Therefore, in this concept article we shall discuss the following  handy list of tips that you can remember about numbers (think about each one of these):

Properties of Number line and Numbers:

-1.5.

For e.g. If there are two rational numbers 2 and 3 , there will always be a rational no. between them.

For e.g. if there are two numbers 2 and 3 then 2 + 3 = 3 + 2

For e.g. if there are two numbers 2 and 3, then

Properties of Zero

Zero is a very important number and has some peculiar properties. Let’s take a look at its properties.

  1. a x 0 = 0 always for any real number a.
  2. a + 0 = a always for any real number a.
  3. a – 0 = a always and 0 – a = -a for any real number a.
  4. 0/a = 0 when “a” is a non-zero real number.
  5. a/0 is not defined i.e. we don’t define division by zero.
  6. a0=1 for any non-zero real number a.
  7. 00 is not defined.

Properties of Addition of Natural Numbers:

  1. Sum of first n natural numbers =

Derivation :-

Let us first understand this by an example . We will generalize this later.

Suppose we have to find sum of  1,2,3,4,5,6 . We know that this is an arithmetic series . In arithmetic series,  first no. + last no. = second +second last = third +third last  .. so on.

1+ 6 =2 + 5 =3 + 4

In each group the sum is 7 . The total number of groups made by 6 numbers are  3.

So, sum of the numbers  = 7 × 3 = 21

Now, let us generalize this method.

First n natural numbers= 1,2,3, …………………. (n-2),(n-1),n

We know that this is an arithmetic series. In arithmetic series,  first no. + last no. = second number +second last number = third number +third last number  .. so on.

1+n =2+n-1=3+n-2 =……

This can be simplified as n+1=n+1=n+1 = ……

In each group, the sum is n+1. Total number of groups made by n numbers are  n/2

So, the sum is

  1. Sum of first n even numbers =>

Derivation: –

Series of even numbers will 2+4+6+8……… 2n

This is an arithmetic series

Sum of arithmetic series =

Sum of arithmetic series = =n(n+1)

  1. Sum of first n odd numbers =

Derivation :-

Series of odd numbers will 1+3+5+……….(2n-1)

This is an arithmetic series

Sum of arithmetic series =

Sum of arithmetic series = =

  1. Sum of squares of first n natural numbers =>
  2. Sum of cubes of first n natural numbers =>
  3. Sum of cubes of 1st ‘n’ Odd natural number =  13 + 33 + 53 + ….. + (2n -1)3 = n2 (2n2 -1)
  4. Sum of cubes of 1st ‘n’ Even natural number  =  23 + 43 + 63 + ….. + (2n)3 = 2 [n (n + 1)]2

Tip: Remember the above-mentioned formulas by heart. They have a  wide application in not just number system but in other topics of quant as well.

Some examples for the above properties:

Find the sum of:

(A) First 30 natural numbers

(B) Squares of first 30 natural numbers

(C) Cubes of first 30 natural numbers

(D) First 30 odd natural numbers

(E) Squares of first odd 30 natural numbers

(F) Squares of first even 30 natural numbers

(G) Cubes of first odd 30 natural numbers

(H) Cubes of first even 30 natural numbers

Solution:

(A) 1 + 2 + 3 +…………………..+ 29 + 30 =   = 15 × 31 = 465

(B) 12 + 22 + 32 + ….. + 302 =   = 5 × 31 × 61 = 9455

(C) 13 + 23 + 33+ ….. + 303 = (15 × 31)2  = 216225

(D) 1+ 3 + 5 + ………. + 57 + 59  = 302 = 900

(E) 12 + 32 + 52 + ….. + (59) 2= 10 ×59 × 61= 35990

(F)  22 + 42 + 62 + ….. + 602 =  = 20(31)(61)= 37820

(G) 13 + 33 + 53 + ….. + (59)3 = 302× (2(30)2 -1) =1619100

(H) 23 + 43 + 63 + ….. + 603 = 2 × [30 × 31]= 2 × [30 × 31]2   =1729800

Let us practice more questions.

EXERCISE:

Question 1: Find the sum of first 20 odd natural numbers.

a. 400

b. 200

c. 4000

d. 420

Answer and Explanation

Solution:  Sum of first n odd numbers =

So, the sum of first 20 odd natural numbers = 202 = 400. Hence, option (a)

Question 2: Find the sum of first 20 even numbers.

a. 400

b. 200

c. 4000

d. 420

Answer and Explanation

Solution:  Sum of first n even numbers =

So, the sum of first 20 even natural numbers = 20 × 21 = 420

Hence, option (d)

Question 3:  Find the sum of first 10 natural numbers.

a. 55

b. 110

c. 220

d. 100

Answer and Explanation

Solution:  Sum of first ‘n’ natural numbers =

So, the sum of first 10 natural numbers = .Hence, option (a)

Question 4: Find the sum of cubes of first 20 odd natural numbers.

a. 419600

b. 319600

c. 960000

d. 628000

Answer and Explanation

Solution:  The sum of cubes of first n odd natural numbers = n2 (2n2 -1)

So, the sum of cubes of first 20 odd natural numbers = 202(2 × 202 – 1) = 400 × 799 = 319600

Hence, option (b)

Question 5: Find the sum of cubes of first 20 even natural numbers.

a. 319600

b. 352800

c. 705600

d. 420000

Answer and Explanation

Solution:  The sum of cubes of first n even natural numbers = 2 [n (n + 1)]2

So, the sum of cubes of first n even natural numbers   = =352800

Hence, option (b)

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