Deepinder’s age is 1/6th of her father’s age. Deepinde’s father’s age will be twice the age of Maninder’s age after 10 years. If Maninder’s eight birthdays was celebrated two years before, then what is Deepinder’s present age.

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Consider Deepinder’s present age to be = x
Then her father’s age is = 6x

It is given that Deepinder ‘s father’s age will be twice the age of Maninder’s age after 10 years Maninder’s age after 10 years = ½(6x + 10) = 3x + 5

Also given that Maninder’s eight birthdays was celebrated two years before. Maninder’s age after 10 years = 8 + 12 = 20

3x + 5 = 20 x = 15/3 = 5

Deepinder ‘s present age = 5 years

5 years

Let deepender’s present age is D, her father is F yrs old and Maninder is M

D=F/6

F+10= 2(M+10) , so F=2M+10

2 yrs ago maninder was 8 yrs old this means now he is 10 yrs old, so M=10

so, F = 30, this gives

D= 30/6 = 5 yrs old.

perfect answer..:)

5 years

Solution:

6d=f (1)

f+10=2(m+10) ==> f=2m+10 (2)

m=8+2=10 (3)

From 2 nd 3

f=30

Therfore d=5

Answer: 5 years old.

5yrs

5 yr 8 months

5 years

6

Deepinder’s present age 5 years