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Algebra: Basics Test-4
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Question 1 |
If p = 0.25, q = −0.05, r = 0.5, then the value of
$ \displaystyle \frac{{{p}^{2}}-{{q}^{2}}-{{r}^{2}}-2pq}{{{p}^{2}}+{{q}^{2}}-2qr-{{r}^{2}}}$
$ \displaystyle \frac{{{p}^{2}}-{{q}^{2}}-{{r}^{2}}-2pq}{{{p}^{2}}+{{q}^{2}}-2qr-{{r}^{2}}}$
$ \displaystyle \frac{7}{8}$ | |
$ \displaystyle \frac{8}{9}$ | |
$ \displaystyle \frac{1}{8}$ | |
$ \displaystyle \frac{5}{8}$ |
Question 1 Explanation:
$ \displaystyle \begin{array}{l}\frac{{{p}^{2}}-{{q}^{2}}-{{r}^{2}}-2qr}{{{p}^{2}}+{{q}^{2}}-2pq-{{r}^{2}}}\\=\frac{{{p}^{2}}-\left( {{q}^{2}}+{{r}^{2}}+2qr \right)}{\left( {{p}^{2}}+{{q}^{2}}-2pq \right)-{{r}^{2}}}\\=\frac{{{p}^{2}}-{{\left( q+r \right)}^{2}}}{{{\left( p-q \right)}^{2}}-{{r}^{2}}}\\=\frac{\left( p+q+r \right)\left( p-q-r \right)}{\left( p-q+r \right)\left( p-q-r \right)}\\=\frac{p+q+r}{p-q+r}=\frac{0.25-0.05+0.5}{0.25+0.05+0.5}\\=\frac{0.7}{0.8}=\frac{7}{8}\end{array}$
Question 2 |
If a x b = a2+ b2–ab, then the value of 9 × 11 is
103 | |
113 | |
119 | |
129 |
Question 2 Explanation:
$ \displaystyle \begin{array}{l}a\times b={{a}^{2}}+{{b}^{2}}-ab\,\left( Given \right)\\\Rightarrow 9\times 11={{9}^{2}}+{{11}^{2}}-3\times 11\\=81+121-99\\=202-99=103\end{array}$
Question 3 |
If p = 999, then the value of
$ \displaystyle 3\sqrt{p\left( {{p}^{2}}+3p+3 \right)+1}$
$ \displaystyle 3\sqrt{p\left( {{p}^{2}}+3p+3 \right)+1}$
1000 | |
999 | |
998 | |
1002 |
Question 3 Explanation:
p= 999 (Given)
$ \displaystyle \begin{array}{l}Now,\,3\sqrt{p\left( {{p}^{2}}+3p+3 \right)+1}\,\\3\sqrt{{{p}^{3}}+3{{p}^{2}}+3p+1}\,\\=3\sqrt{{{\left( p+1 \right)}^{3}}}\,=p+1\\=333+1=1000\end{array}$
$ \displaystyle \begin{array}{l}Now,\,3\sqrt{p\left( {{p}^{2}}+3p+3 \right)+1}\,\\3\sqrt{{{p}^{3}}+3{{p}^{2}}+3p+1}\,\\=3\sqrt{{{\left( p+1 \right)}^{3}}}\,=p+1\\=333+1=1000\end{array}$
Question 4 |
If 55a + 5=1, then a equals
-1 | |
-2 | |
3/5 | |
-4/5 |
Question 4 Explanation:
$ \displaystyle \begin{array}{l}{{5}^{5a+5}}=1\\\Rightarrow {{5}^{5a}}\times {{5}^{5}}\Rightarrow {{5}^{5a}}=\frac{1}{{{5}^{5}}}\\\Rightarrow {{5}^{5a}}={{5}^{-5}}\Rightarrow 5a-5\\\Rightarrow a=-1\end{array}$
Question 5 |
If 3r+3+7=250, then r is equal to
4 | |
6 | |
2 | |
8 |
Question 5 Explanation:
$ \displaystyle \begin{array}{l}{{3}^{r+3}}+7=250\\\Rightarrow {{3}^{r+3}}=243\,\,\,\,\,\,\,\,\Rightarrow {{3}^{r+3}}={{3}^{5}}\\\Rightarrow r+3=5\Rightarrow r=2\end{array}$
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