Arithmetic: Percentage Test -2

This is an assessment test.
To draw maximum benefit, study the concepts for the topic concerned.
Kindly take the tests in this series with a pre-defined schedule.

Arithmetic: Percentage Test -2

Please wait while the activity loads.
If this activity does not load, try refreshing your browser. Also, this page requires javascript. Please visit using a browser with javascript enabled.

If loading fails, click here to try again

Congratulations - you have completed Arithmetic: Percentage Test -2.You scored %%SCORE%% out of %%TOTAL%%.You correct answer percentage: %%PERCENTAGE%% .Your performance has been rated as %%RATING%%

Your answers are highlighted below.

Question 1

In an examination, 40% marks are required to pass. A obtains 10% less than the number of marks required to pass. B obtains 11¹/₉ % less than A and C obtained 41³/₁₇% less than the number of marks obtained by A and B together. What marks did C get?

A	50
B	40
C	35
D	45

Question 1 Explanation:

Let the total marks be 100
Minimum marks required to pass the exam =40
Marks obtained by A = 40 – (40 x 10/100) = 36 marks
Marks obtained by B= 36 – (100/9 x 36/100) = 32 marks
Marks obtained by C ==(36 +32) x 700/(17 x100)=40 marks

Question 2

An article is listed at Rs 65. A customer bought this article for Rs 56.16 with two successive discounts, out of which one is 10%. The other discount of this discount scheme that was allowed by the shopkeeper is:

A	4%
B	3%
C	6%
D	2.5%

Question 2 Explanation:

let the discount be D
Therefore 65 x (90)/100 x (100 –D)/100 = 56.16
100 – D = (56.16 x 100 x100) / (65 x 9)
100 – D = 96
D = 4%

Question 3

Mohan spends 40% of his salary on food items, 50% of the remaining on transport, 30% of the remaining on clothes , after spending on food and transport; and saves the balance. If he saves Rs 630 every month, what is his monthly salary?

A	Rs 1500
B	Rs 3000
C	Rs 5000
D	Rs 6500

Question 3 Explanation:

4s/10 + (10s-4s)/10 x 50/100 +(6s-3s)/10 x 30/100 + saving = s
4s/10 + 6s/10 x 50/100 +3s/10 x 30/100 + saving = s
=> 4s/10 + 3s/10 + 9s/100 + 630 =s
=> 630 = (100s - 70s – 9s)/100
=> 630 = 21s/100
=> s = Rs 3000

Question 4

The wheat sold by a grocer contained 10% low quality wheat. What quantity of good quantity wheat should be added to 150 kg of wheat so that the percentage of low quality wheat becomes 5%?

A	85 kg
B	50 kg
C	135 kg
D	150 kg

Question 4 Explanation:

First, let’s calculate the low quality wheat: 10% of 150 = 15
This 15kg should now be 5% of the total amount of wheat.
Therefore the total amount of wheat becomes 300 kg
Originally, the wheat which is of good quality was 150 -15 =135kg
To become 5% low quality of wheat, we add the 150kg of good quality wheat.

Question 5

The present population of a village is 5500. If the number of males increases by 11 % and the number of females increases by 20%, then the population will become 6330. What is the present population of females in the village?

A	3000
B	3500
C	2500
D	2000

Question 5 Explanation:

Let the present population of male = m
Let the present population of female = f
So m + f= 5500................................................1
111/100m +120/100f =6330
111m +120f =633000....................................2
On solving 1 and 2
f = 2500

Once you are finished, click the button below. Any items you have not completed will be marked incorrect. Get Results

There are 5 questions to complete.

←

List

→

Return

Shaded items are complete.

1	2	3	4	5
End

Return

Concept Articles

Exercises

Practice Tests

How to study this lesson?

It is actually simple to study this lesson.
Go through the given concepts and their corresponding exercises.
Then, solve the percentage practice tests and perfect the skills you have learnt