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## Arithmetic: Time Speed Distance Test-8

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Question 1 |

Two trains start from stations A and B and travel towards each other at speeds of 50 km/hour and 60 km/hour respectively. At the time of their meeting, the second train has travelled 120 km more than the first. The distance between A and B is:

990 km | |

1200 km | |

1320 km | |

1440 km |

Question 1 Explanation:

The speed of B is 10 Km/hr more than A.

Therefore the difference of 120 km must have been created in =120/10 = 12 hrs.

The relative speed = 110 Km/hr.

The total distance is 110 km/hr X 12 = 1320 Km

Correct option is (c).

Therefore the difference of 120 km must have been created in =120/10 = 12 hrs.

The relative speed = 110 Km/hr.

The total distance is 110 km/hr X 12 = 1320 Km

Correct option is (c).

Question 2 |

Two trains are moving on two parallel tracks but in opposite directions. A person sitting in the train moving at the speed of 80 km/hr passes the second train in 18 seconds. If the length of the seconds train is 1000m, its speed is

100 km./hr. | |

120 km./hr. | |

140 km./hr. | |

150 km./hr. |

Question 2 Explanation:

We have to consider the negligible distance contributed by the 1st train

as only the man is to be considered.

Therefore, 1000 m is to be traveled in 18 sec.

speed in km/hr is (1000/18) x (18/5) = 200km/h This is the relative speed of two trains.

Therefore the speed of 2nd train is 200-80 = 120 Km/h

as only the man is to be considered.

Therefore, 1000 m is to be traveled in 18 sec.

speed in km/hr is (1000/18) x (18/5) = 200km/h This is the relative speed of two trains.

Therefore the speed of 2nd train is 200-80 = 120 Km/h

Question 3 |

Two trains of equal length, running in opposite directions, passes pole in 18 and 12 seconds. The trains will cross each other in

14.4 seconds | |

15.5 seconds | |

18.8 seconds | |

20.2 seconds |

Question 3 Explanation:

Let the length be x m.

total length = 2x m

Speed of one train is x/18 m/s and x/12 m/s.

Total time isÂ =$ \displaystyle \frac{2x}{\frac{x}{18}+\frac{x}{12}}=14.4\sec $

total length = 2x m

Speed of one train is x/18 m/s and x/12 m/s.

Total time isÂ =$ \displaystyle \frac{2x}{\frac{x}{18}+\frac{x}{12}}=14.4\sec $

Question 4 |

Two trains 105 metres and 90 metres long, run at the speeds of 45 km/hr and 72km/hr respectively, in opposite directions on parallel tracks. The time which they take to cross each other, is

8 seconds. | |

6 seconds | |

7 seconds | |

5 seconds |

Question 4 Explanation:

Let the train with length 105 m be marked as A and the second train of length 90m be marked as B..

Speed of A: 45 x 5/18= 25/3 m/s

Speed of B: 72 x 5/18= 20 m/s.

Relative speed = 25/3+20 = 85/3 m/s

Total distance = 195 m

therefore the time taken is

$ \frac{195}{(72+45)\times \frac{5}{18}}=6\sec $

Speed of A: 45 x 5/18= 25/3 m/s

Speed of B: 72 x 5/18= 20 m/s.

Relative speed = 25/3+20 = 85/3 m/s

Total distance = 195 m

therefore the time taken is

$ \frac{195}{(72+45)\times \frac{5}{18}}=6\sec $

Question 5 |

A train, 150m long, passes a pole in 15 seconds and another train of the same length travelling in the opposite direction in 12 seconds. The speed of the seconds train is

45km./hr. | |

48km./hr. | |

52km./hr. | |

54km./hr. |

Question 5 Explanation:

Speed of the first train is 150m/15 secs = 10 m/s.

In 12 sec it covers 120 m.

Now the actual distance to cross the train is 150 +150 =300 m.

Therefore the second train travels at 300 -120 = 180 m in 12 secs.

Speed of 2

In 12 sec it covers 120 m.

Now the actual distance to cross the train is 150 +150 =300 m.

Therefore the second train travels at 300 -120 = 180 m in 12 secs.

Speed of 2

^{nd}train is 15 m/s. = 15 x 18 /5 = 54 Km /hr.
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