- This is an assessment test.
- These tests focus on the basics of Maths and are meant to indicate your preparation level for the subject.
- Kindly take the tests in this series with a pre-defined schedule.

## Basic Maths: Test 12

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Question 1 |

$ \displaystyle 10-\left[ 4-\left\{ 3-\left( 3-3-6 \right) \right\} \right]$ is equal to:

15 | |

16 | |

14 | |

10 |

Question 1 Explanation:

$ \displaystyle \begin{array}{l}p=10-\left[ 4-\left\{ 3-\left( 3-3-6 \right) \right\} \right]\\=10-\left[ 4-\left\{ 3-\left( -6 \right) \right\} \right]\\=10-\left[ 4-\left\{ 3+6 \right\} \right]\\=10-\left[ 4-9 \right]\\=10+5=15\end{array}$

Question 2 |

Evaluate:$ \displaystyle \frac{-{{\left( 4-6 \right)}^{2}}-3\left( -2 \right)+6}{17-9\div 3\times 5}$

$ \displaystyle \frac{3}{8}$ | |

$ \displaystyle 7$ | |

$ \displaystyle 4$ | |

$ \displaystyle \frac{7}{4}$ |

Question 2 Explanation:

$ \displaystyle \begin{array}{l}?=\frac{-{{\left( -2 \right)}^{2}}+6+6}{17-15}\\=\frac{-4+12}{2}=\frac{8}{2}=4\end{array}$

Question 3 |

Simplify: $ \displaystyle \frac{\frac{5}{3}\times \frac{7}{51}of\,\frac{17}{5}-\frac{2}{3}}{\frac{2}{9}\times \frac{5}{7}of\,\frac{28}{5}-\frac{1}{3}}$

$ \displaystyle \frac{1}{2}$ | |

$ \displaystyle 4$ | |

$ \displaystyle \frac{1}{5}$ | |

$ \displaystyle \frac{1}{4}$ |

Question 3 Explanation:

Question 4 |

$ \displaystyle 3-\left[ 5-\left\{ 2+\left( -5+6-2 \right)2 \right\} \right]$ is equal to

-4 | |

2 | |

0 | |

-2 |

Question 4 Explanation:

$ \displaystyle \begin{array}{l}p=3-\left[ 5-\left\{ 2+\left( -1 \right)2 \right\} \right]\\=3\times \left[ 5-\left\{ 2-2 \right\} \right]\\=3-\left[ 5-0 \right]\\=3-5=-2\end{array}$

Question 5 |

On simplification 2134âˆ’(1002/20.04) is equal to:

3029 | |

2084 | |

2993 | |

2543 |

Question 5 Explanation:

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