- This is an assessment test.
- These tests focus on the basics of Maths and are meant to indicate your preparation level for the subject.
- Kindly take the tests in this series with a pre-defined schedule.

## Basic Maths: Test 17

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Question 1 |

$\displaystyle \left[ 3\frac{1}{4}\div \left\{ 1\frac{1}{4}-\frac{1}{2}\left( 2\frac{1}{2}-\frac{1}{4}-\frac{1}{6} \right) \right\} \right]\,\div \left( \frac{1}{2}\,of\,4\frac{2}{3} \right)$

18.76 | |

36.89 | |

33.42 | |

78.54 |

Question 1 Explanation:

Question 2 |

The value of $ \displaystyle 8\div \left[ 1+1\div \{1+1\div \left( 1+1\div 2 \right)\} \right]$Â is

$ \displaystyle 1$ | |

$ \displaystyle 5$ | |

$ \displaystyle 2$ | |

$ \displaystyle \frac{1}{2}$ |

Question 2 Explanation:

$ \displaystyle \begin{array}{l}=8\div \left[ 1+1\div \left\{ 1+1\div \left( 1+1\div 2 \right) \right\} \right]\\=8\div \left[ 1+1\div \left\{ 1+1\div \left( 1+\frac{1}{2} \right) \right\} \right]\\=8\div \left[ 1+1\div \left\{ 1+1\div \frac{3}{2} \right\} \right]\\=8\div \left[ 1+1\div \left\{ 1+\frac{2}{3} \right\} \right]\\=8\div \left[ 1+1\div \frac{5}{3} \right]\\=8\div \left[ 1+\frac{3}{5} \right]\\=8\div \frac{8}{5}=5\end{array}$

Question 3 |

The simplified value ofÂ Â

$ \displaystyle \frac{\frac{1}{3}\div \frac{1}{3}\times \frac{1}{3}}{\frac{1}{3}\div \frac{1}{3}\,of\,\frac{1}{3}}-\frac{1}{3}$

$ \displaystyle \frac{\frac{1}{3}\div \frac{1}{3}\times \frac{1}{3}}{\frac{1}{3}\div \frac{1}{3}\,of\,\frac{1}{3}}-\frac{1}{3}$

$ \displaystyle 0$ | |

$ \displaystyle 1$ | |

$ \displaystyle \frac{1}{3}$ | |

$ \displaystyle -\frac{2}{9}$ |

Question 3 Explanation:

The given expression is

$ \displaystyle \begin{array}{l}=\frac{\frac{1}{3}\div \frac{1}{3}\times \frac{1}{3}}{\frac{1}{3}\div \left( \frac{1}{3}\,\times \,\frac{1}{3} \right)}-\frac{1}{3}\\=\frac{\frac{1}{3}}{\frac{1}{3}\div \frac{1}{3}}-\frac{1}{3}\\=\frac{\frac{1}{3}}{\frac{1}{3}\times 9}-\frac{1}{3}\\=\frac{\frac{1}{3}}{3}-\frac{1}{3}\\=\frac{1}{9}-\frac{1}{3}=-2/9\end{array}$

$ \displaystyle \begin{array}{l}=\frac{\frac{1}{3}\div \frac{1}{3}\times \frac{1}{3}}{\frac{1}{3}\div \left( \frac{1}{3}\,\times \,\frac{1}{3} \right)}-\frac{1}{3}\\=\frac{\frac{1}{3}}{\frac{1}{3}\div \frac{1}{3}}-\frac{1}{3}\\=\frac{\frac{1}{3}}{\frac{1}{3}\times 9}-\frac{1}{3}\\=\frac{\frac{1}{3}}{3}-\frac{1}{3}\\=\frac{1}{9}-\frac{1}{3}=-2/9\end{array}$

Question 4 |

Simplify

$ \displaystyle \frac{2\frac{3}{4}}{1\frac{5}{6}}\div \frac{7}{8}\times \left( \frac{1}{3}+\frac{1}{4} \right)+\frac{5}{7}\div \frac{3}{4}\,\,of\,\frac{4}{7}$

$ \displaystyle \frac{2\frac{3}{4}}{1\frac{5}{6}}\div \frac{7}{8}\times \left( \frac{1}{3}+\frac{1}{4} \right)+\frac{5}{7}\div \frac{3}{4}\,\,of\,\frac{4}{7}$

$ \displaystyle \frac{56}{77}$ | |

$ \displaystyle \frac{49}{80}$ | |

$ \displaystyle 2\frac{2}{3}$ | |

$ \displaystyle 3\frac{2}{9}$ |

Question 4 Explanation:

The given expression
$ \displaystyle \begin{array}{l}\frac{\frac{11}{4}}{\frac{11}{6}}\div \frac{7}{8}\left( \frac{4+3}{12} \right)+\frac{5}{7}\div \frac{3}{4}\,\,of\,\,\frac{4}{7}\\=\left( \frac{11}{4}\times \frac{6}{11} \right)\div \frac{7}{8}\times \frac{7}{12}+\frac{5}{7}\div \left( \frac{3}{4}\times \frac{4}{7} \right)\\=\frac{3}{2}\div \frac{7}{8}\times \frac{7}{12}+\frac{5}{7}\div \frac{3}{7}\\=\frac{3}{2}\times \frac{8}{7}\times \frac{7}{12}+\frac{5}{7}\div \frac{3}{7}\\=1+\frac{5}{3}\\=\frac{8}{3}\\=2\frac{2}{3}\end{array}$

Question 5 |

The value of <br>$ \displaystyle \sqrt{4+\sqrt{11+\sqrt{19+\sqrt{29+\sqrt{49}}}}}$ <br>is

$ 2\sqrt{2}$ | |

$ {2}/{\sqrt{2}}\;$ | |

$ 7$ | |

$ 5$ |

Question 5 Explanation:

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