- This is an assessment test.
- These tests focus on the basics of Maths and are meant to indicate your preparation level for the subject.
- Kindly take the tests in this series with a pre-defined schedule.

## Basic Maths: Test 4

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Question 1 |

54.5% of 600 + 30.5% of 1800 = (p)

^{2}+200+36 or -36 | |

+26 or -26 | |

â€“81 or +81 | |

none |

Question 1 Explanation:

$ \displaystyle \begin{array}{l}\frac{54.5\times 600}{100}+\frac{30.5\times 1800}{100}={{p}^{2}}+200\\\Rightarrow 327+549={{p}^{2}}+200\\\Rightarrow 876={{p}^{2}}+200\\\Rightarrow {{p}^{2}}=876-200=676\\Therefore\,\,p=\sqrt{676}=\pm 26\end{array}$

Question 2 |

$ \displaystyle \sqrt{{{7}^{2}}\times 6+\left( {{15}^{2}} \right)+57}=p$

24 | |

(519) ^{1/2} | |

519 | |

529 |

Question 2 Explanation:

$ \displaystyle \begin{array}{l}p=\sqrt{49\times 6+225+57}\\=\sqrt{294+225+57}\\=\sqrt{576}=24\end{array}$

Question 3 |

Find the value of p?
$ \displaystyle \sqrt{625.04}\times 16.94+204.001\div 17=p$

4.18 | |

4.41 | |

425 | |

437 |

Question 3 Explanation:

Taking approximate values

$ \displaystyle \begin{array}{l}p=\sqrt{625}\times 17+204\div 17\\=25\times 17+204\times \frac{1}{17}\\=425+12=437\end{array}$

$ \displaystyle \begin{array}{l}p=\sqrt{625}\times 17+204\div 17\\=25\times 17+204\times \frac{1}{17}\\=425+12=437\end{array}$

Question 4 |

$ \displaystyle 0.34\overline{33}+0.13\overline{33}=?$

$ \displaystyle 0.47$ | |

$ \displaystyle 0.47\overline{66}$ | |

$ \displaystyle 0.\overline{48}$ | |

$ \displaystyle 4.\overline{8}$ |

Question 4 Explanation:

$ \displaystyle \begin{array}{l}0.34\overline{33}+0.13\overline{33}\\=\frac{3433-34}{9900}+\frac{1333-13}{9900}\\=\frac{3399+1320}{9900}=\frac{4719}{9900}\\=\frac{4766-47}{9900}=0.47\overline{66}\end{array}$

Question 5 |

28.217 â€“ 14.241 + 6.873 â€“ 2.434 =p

9.419 | |

18.545 | |

16.275 | |

none |

Question 5 Explanation:

$ \displaystyle p=28.217-14.241+6.873-2.434=18.415$

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